Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 8 of 12.
Suvas said:
9 years ago
How you got 3508?
Lavanya said:
9 years ago
Any other easy way to solve immediately.
And wish formula use.
And wish formula use.
Guru said:
9 years ago
Any other easy way to solve immediately.
Manikant Thakur said:
10 years ago
In the question it is not mention that A having x or B having x so I am confuse here I got these two answer 7500 & 6400 so which should be the right one?
VinithaGopal said:
10 years ago
How this 28x-22x = 350800-(13900 x 22) came ? Please somebody explain!
Lakshman said:
10 years ago
Anyone please can explain how it came 45000?
Jay said:
1 decade ago
We can solve this problem this way - I = Pti when i=interest, p= actual amount, i=rate of interest, t=time.
Eeswar kumar said:
1 decade ago
By using simple formula [(I*100-P*R2)/R1-R2] = P2.
Here p = Total amount shared between A & B as P = P1+P2.
I = Total interest; R1 = P1's rate of interest, R2 = P2's rate of interest.
Here p = Total amount shared between A & B as P = P1+P2.
I = Total interest; R1 = P1's rate of interest, R2 = P2's rate of interest.
Priya said:
1 decade ago
Can anyone solve by taking x as a value of B? Am getting different answer if I take x for B.
Mahesh said:
1 decade ago
@King Kartik.
Formula : RT = (n-1)100.
Here: N = 2 (amount is double).
T = 5yr.
R?
Then 5R = 100.
R = 100/5.
R = 20.
Formula : RT = (n-1)100.
Here: N = 2 (amount is double).
T = 5yr.
R?
Then 5R = 100.
R = 100/5.
R = 20.
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