Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 8 of 12.
Ganesh said:
1 decade ago
Someone's tell me how did you get 3508? Please answer me.
Ajay said:
5 years ago
By using alligation method, we get;
13900/30*14 = 6500.
13900/30*14 = 6500.
(1)
Punna vandana said:
8 years ago
Please, can anyone explain this problem in percentages?
Priya said:
6 years ago
How this is calculated? I didn't get please explain it.
(1)
Krishna Kant Sharma said:
9 years ago
Thanks for giving the solution. I understand it now.
Sri said:
8 years ago
@Depu.
Thanks for giving the explanation of answer.
Thanks for giving the explanation of answer.
Heetu said:
1 decade ago
Please give me any simple way I cant understand it.
Anky said:
1 decade ago
Can some one explain why we took x and 13900 - x.
Ashwini said:
1 decade ago
How to take rate percentages? Please explain me
Suchita said:
1 decade ago
@Rajesh.
Can you please tell me that method.
Can you please tell me that method.
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