Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Rs. 6400
Rs. 6500
Rs. 7200
Rs. 7500
None of these
Answer: Option
Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100

28x - 22x = 350800 - (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Video Explanation: https://youtu.be/Xi4kU9y6ppk

Discussion:
115 comments Page 7 of 12.

MANI SMART said:   1 decade ago
The formula is (pnr/100).

p=inicial amount,
n=no of years,
r=rate of interest

Nagaraju said:   9 years ago
Here why we had taken (13900 - x)?

Please, can anyone explain it in detail?

Swati Alone said:   1 decade ago
Can anyone tell me how to do this answer easily and fast without using pen ?

Dorji bhai said:   5 years ago
How denominator is getting cancelled while adding? Please explain about it.
(1)

Monica Williams said:   6 years ago
3508 *100 (÷ will become*) so that's how we got 350800 in the 2nd step?

VinithaGopal said:   10 years ago
How this 28x-22x = 350800-(13900 x 22) came ? Please somebody explain!

Anu said:   1 decade ago
In this explanation how - 22x will come can any one explain me.

Lavanya said:   9 years ago
Any other easy way to solve immediately.

And wish formula use.

Chinnaribunga said:   9 years ago
How it came 45000? I didn't understand this, Please tell me.

Swati said:   7 years ago
Why it has not taken X for B's principal? Please explai me.
(2)


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