Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 9 of 12.
Yuki said:
4 years ago
Thanks all for explaining the answer clearly.
(8)
Viji said:
1 decade ago
Please explain how do you get 7500 and 6400.
Lakshman said:
10 years ago
Anyone please can explain how it came 45000?
Ramesh k said:
9 years ago
Can any one one solve this in simple method?
Kasamsetty Deepshika said:
4 years ago
What if I take A as 13900-x? Please explain.
(8)
Saurabh chavan said:
9 years ago
Please, anybody explain it in a simple way.
Sumit said:
9 years ago
Please explain me. I can't understand this.
Soumya said:
9 years ago
Can anyone explain it in Alligation method?
Lucy said:
8 years ago
350800 - (13900 x 22) =45000 How its came?
Maheswaran said:
9 years ago
Thanks for the solution and explanations.
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