Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 5 of 12.
Manish said:
8 years ago
Let x be the amount of B and 13900-x be the amount of A then without subtract we can find the value o B.
Madhu said:
8 years ago
@Phani Kumar
Can you please solve using the formula you stated?
i.e P1= {(100*1)-(PTR2)} / (R1-R2),
P2=P-P1.
Please anyone help me with this solution.
Can you please solve using the formula you stated?
i.e P1= {(100*1)-(PTR2)} / (R1-R2),
P2=P-P1.
Please anyone help me with this solution.
Sri said:
8 years ago
@Depu.
Thanks for giving the explanation of answer.
Thanks for giving the explanation of answer.
Krishna Kant Sharma said:
9 years ago
Thanks for giving the solution. I understand it now.
Loke said:
9 years ago
Let A amount be "x" rupees so B must be "13900-x "(because 13900 divided two members we don't know the exact amount so we consider "x" rs by A remaining amount 13900-x by B).
Apply formula.
PTR/100.
P = PRINCIPAL
T = TIME
R = RATE OF INTEREST
X * 14 * 2/100 + (13,900-X) * 11 * 2/100 = 3508.
(x is the principal amount we don't know),
(14 is rate of interest A),
(2 is the year),
After calculation we get 6400.
Apply formula.
PTR/100.
P = PRINCIPAL
T = TIME
R = RATE OF INTEREST
X * 14 * 2/100 + (13,900-X) * 11 * 2/100 = 3508.
(x is the principal amount we don't know),
(14 is rate of interest A),
(2 is the year),
After calculation we get 6400.
Chandrasekar.S said:
9 years ago
Anyone can solve it in easy way?
REKHA said:
9 years ago
Thank you all for giving the solution.
Paply said:
9 years ago
Anyone can solve it in easy way? Please.
Harsha said:
9 years ago
Can anyone explain easily?
PRANAV said:
9 years ago
@Bushra.
Area of rectangle = l * w
Perimeter of rectangle = 2 * (l + w)
--------------------------------------------
2 * (l + w) = 200
l + w = 100 ---> equa(1)
l * w = 2400
so, w = 2400/l ---> equa(2)
Putting equa(2) in equa(1).
We get,
l + (2400/l) = 100
l^2 + 2400 = 100 * l
l^2 - 100 * l -2400 = 0
l^2 - 60 * l - 40 * l -2400 = 0
l (l - 60) - 40 (l - 60) = 0
(l - 60) (l - 40) = 0
Hence, if l = 60 w = 40 (from equa(1))
Else, l = 40 then w = 60.
Area of rectangle = l * w
Perimeter of rectangle = 2 * (l + w)
--------------------------------------------
2 * (l + w) = 200
l + w = 100 ---> equa(1)
l * w = 2400
so, w = 2400/l ---> equa(2)
Putting equa(2) in equa(1).
We get,
l + (2400/l) = 100
l^2 + 2400 = 100 * l
l^2 - 100 * l -2400 = 0
l^2 - 60 * l - 40 * l -2400 = 0
l (l - 60) - 40 (l - 60) = 0
(l - 60) (l - 40) = 0
Hence, if l = 60 w = 40 (from equa(1))
Else, l = 40 then w = 60.
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