Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 10 of 12.
Sree said:
7 years ago
Good explanation. Thank you all.
(1)
Priya said:
7 years ago
Thank you so much @Jitendar.
(1)
Mangesh said:
7 years ago
P=13900
A=14%
B=11%
So,total SI= 3508.
Hence we need to fine out B scheme.
Use option given 1st option is 6400,
6400*2 year*11%÷100=1408,
And remaining intrest is 3508-1408=2100,
Now A scheme,
13900-6400=7500,
7500*2year*14%÷100=2100.
A=14%
B=11%
So,total SI= 3508.
Hence we need to fine out B scheme.
Use option given 1st option is 6400,
6400*2 year*11%÷100=1408,
And remaining intrest is 3508-1408=2100,
Now A scheme,
13900-6400=7500,
7500*2year*14%÷100=2100.
(1)
Swati said:
7 years ago
Why it has not taken X for B's principal? Please explai me.
(2)
Umesh gandla said:
7 years ago
x x 14 x 2 + (13900 - x) x 11 x 2 = 3508.
100 100
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
100 100
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
(2)
Vikas said:
6 years ago
step 1= p*r*t/100.
step 2=A=X & B=Y,
step 3= (X*14/100*2/2)+(Y*11/100*2/2)=3508/2.
step 4=X+y=3508,
After calculation we get x and y value.
step 2=A=X & B=Y,
step 3= (X*14/100*2/2)+(Y*11/100*2/2)=3508/2.
step 4=X+y=3508,
After calculation we get x and y value.
Hari Priyan said:
6 years ago
Assume that the principal invested in scheme A be rupees x.
Then according to question the principal invested in scheme B is (13900-x) rupees.
Number of years: 2 years.
Rate of interest in scheme A:14%.
Rate of interest in scheme B: 11%.
Total interest earned : rs 3508.
SI: PNR/100 formula.
(x*2*14/100)+((13900-x)*2*11/100)=3508.
(28x/100)+((305800-22x)/100)=3508.
(28x-22x)+305800=3508*100.
6x+305800=350800,
6x=350800-305800,
6x=45000,
x=7500.
Now we got x ie.. principal invested in scheme A.
Now we can find the principal invested in scheme B.
13900-7500= 6400.
Principal invested in scheme B is rupees 6400.
Then according to question the principal invested in scheme B is (13900-x) rupees.
Number of years: 2 years.
Rate of interest in scheme A:14%.
Rate of interest in scheme B: 11%.
Total interest earned : rs 3508.
SI: PNR/100 formula.
(x*2*14/100)+((13900-x)*2*11/100)=3508.
(28x/100)+((305800-22x)/100)=3508.
(28x-22x)+305800=3508*100.
6x+305800=350800,
6x=350800-305800,
6x=45000,
x=7500.
Now we got x ie.. principal invested in scheme A.
Now we can find the principal invested in scheme B.
13900-7500= 6400.
Principal invested in scheme B is rupees 6400.
Monica Williams said:
6 years ago
3508 *100 (÷ will become*) so that's how we got 350800 in the 2nd step?
Anuj said:
6 years ago
With alligation method.
B = 11%.
A = 14%.
Calculate Rate for 1 year on 100*1754/13900*1 = 12.61%.
1754 is one-year int.
mean is 12.61%.
then 14%-12.61% = 1.38%.
12.61-11 = 1.61.
1.38/3*13900 = 6400.
B = 11%.
A = 14%.
Calculate Rate for 1 year on 100*1754/13900*1 = 12.61%.
1754 is one-year int.
mean is 12.61%.
then 14%-12.61% = 1.38%.
12.61-11 = 1.61.
1.38/3*13900 = 6400.
B Krishna said:
6 years ago
How did you Assume that 7500 here, in what basis did you get that, can we get a Clear Explanation on this?
(1)
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