Aptitude - Simple Interest - Discussion

350800 - (13900 x 22) =45000 How its came?

The answer can be 6400 or 7500.

It is not necessary that A will invest X and B will invest the difference.

From the question we know 13900 is the amount he invested.
Let assume, 'x' be the amount invested on A.
so 13900-x be the amount B have

SI=PNR/100.
Case of A:
for 2 years, as per the question.
SI1=x*2*14/100
Similarly
Case of B:
for 2 years
SI2=(13900-x)*2*11/100

its given that the total amount of simple interest is 3508
ie,SI1+SI2=3508

substituting the above two equations
Then, x x 14 x 2 /100 + (13900 - x) x 11 x 2/100 = 3508
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

@Phani Kumar.

Can you plz tell me how to take a difference between r1 and r2 (14% - 11%) or (14*2-11*2).

How 45000 will come? Please explain it.

@Renu.

It has Some correction @Phani Kumar .

Given -----> P = P1+P2 (Principle is divided between two)
Sum of interests on P1 and P2 is given as I = SI1+ SI2 = 3508 S11---> Simple interest on P1
SI2 ---> Simple interest on P2
I = ( P1*T1*R1 /100) + (P2*T2*R2/100)
100*I = (P1*T1*R1) + (P2*T2*R2)
But Given T1= T2=T
so,
100*I /T = P1*R1 + P2*R2
= P1*R1 + (P-P1)*R2
= P1*R1 + P*R2 - P1*R2

(100*I/T) - P*R2 = P1*(R1-R2)
((100*I)-( P*T*R2))/ T = P1*(R1-R2)
P1 = (100*I - P*T*R2) / T*(R1-R2) (R1-R2 = 14 -11 =3)
Find P2 = P - P1

Please, can anyone explain this problem in percentages?

It is a PTR/100 formula total SI is given we find amount invested in B so subtract x from p here x is an amount invested and p total amount. Two different scheme so we add two amount and the SI is placed other side by the formula

SI=P*R*T/100.

In this question money is divided into two parts. On one part he got 14% interest and on other part he got 11%.

The difference is 3%(14%-11%) in one year.
If we got 14% on both then 14% of 13900 = 1946.
But we got interest 3504 which is in two years so in one year 3504/2 =1754.
The difference is 1946-1754=192.
So we got 3% difference on 192.
3% =192.
1%=192/3=64.
100%=6400.
So, one part is 6400 and other (13900-6400) = 7500.

C let us assume that principle invested in a is x.

& b be y.

The total amt invested is 13900,
so x+y=13900 or y=13900-x,
by using formula i=ptr/100,
x*14*2/100 + y*11*2/100,
= 28x/100+22y/100=3508,
28x+22y=350800,

Substitution of y frm 1
28x+22(13900-x) = 350800 now solve.