Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Rs. 6400
Rs. 6500
Rs. 7200
Rs. 7500
None of these
Answer: Option
Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100

28x - 22x = 350800 - (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Video Explanation: https://youtu.be/Xi4kU9y6ppk

Discussion:
115 comments Page 11 of 12.

Sravs said:   6 years ago
Let calculate SI for 14% per anum si = 13900*1*14/100 = 1946,
Caluculate si for 11% per anum si = 13900 * 1 * 11/100 = 1529,

Given intrerest for 2 year so 3508/2 = 1754 p.a.
By using alligation:

1956-1754 = 192
1754 - 1529 = 225.

Tatio;-B:A = 192 : 225.

Sum of B = 13900 * 192/417 = 6400.
(2)

Priya said:   6 years ago
How this is calculated? I didn't get please explain it.
(1)

Ajay said:   5 years ago
By using alligation method, we get;

13900/30*14 = 6500.
(1)

Dorji bhai said:   5 years ago
How denominator is getting cancelled while adding? Please explain about it.
(1)

Siva said:   5 years ago
I can't understand. If we use the formula ptr/100, how to identify 'r' in that? Please explain me.
(1)

K. Uma said:   5 years ago
Let us assume that the scheme A be as X & scheme B be as Y.

The total amount invested is 13900.
So, X+Y=13900
X=13900-Y--------(1).

Now, we use simple interest formula SI=PRT/100
Time T=2years
Per annum R=14% & 11%
Now, substitute the values in SI formula.

Amount invested scheme B=
[Xx14x2/100]+[Yx11x2]=3508
[28X/100] +[22Y/100]=3508
28X+22Y=3508x100
28X+22Y=350800--------------> (2)

Now substitute eq(1) in eq(2).

28(13900-Y) + 22Y = 350800
389200-28Y + 22Y = 350800
- 28Y + 22Y = 350800 - 389200
- 6Y = - 38400.
6Y = 38400.
Y = 38400/6.
Y = 6400.
Amount invested scheme B= 6400.
(6)

Yogeswara Rao said:   5 years ago
Invested money = 13900.
Divided into two schemes A and B.
Let the scheme A = x.
Scheme B = 13900-x.
SI = PTR/100.
SI = x.2.14/100,
SI = 28x/100.

2nd case
SI = (13900-x).2.11/100.
SI = 3508,
3508 = 28x/100+ (13900-x).2.11/100,
350800= 28x +305800-22x,
-45000 = -6x.
X = 45000/6.
X = 7500.
B = 13900 - 7500.
B = 6400.
(12)

Deepak said:   5 years ago
Thanks for explaining @Srini.
(4)

Yuki said:   4 years ago
Thanks all for explaining the answer clearly.
(8)

Sourav Kalal said:   4 years ago
Let me solve it in a simple way.

13900 X 11% = 1529 (They asked for B whose interest is 11%).
2 YR = 3508
1 YR = 1754,

EXTRA INTERST = 1754-1529 = 225.

That extra interest nothing but 14%-11%=3%,
3% = 225,
100% = 7500,
13900-7500 = 6400,
(73)


Post your comments here:

Your comments will be displayed after verification.