Aptitude - Ratio and Proportion - Discussion

It is so simple.

First value of water = 1.
Second value of water = 3.

Therefore:
1/3 * 60 = 20
2/3 * 60 = 40
20 + 40 = 60.

"In a vessel, containing 60 litres of a mixture of milk and water, water is only 30%. 12 litres of the mixture were taken out and X litres of pure milk were added. As a result percentage of water in the mixture became 18%. What is the value of X?" Can anyone please explain?

Milk = 2/3 * 60 = 40;
Water =1/3 * 60 = 20;

Aadd water = x (suppose)
then, 40/(20 + x) = 1:2.

x = 60 -> answer.

Initial mix i.e, 60Ltr Old ration m : w :: 2 : 1 total parts 2 + 1 = 3parts of 60Ltr = 20Ltr.

Hence milk = 2 * 20 = 40Ltr, & water = 1 * 20 = 20Ltr.

But question is how much further or additional water is added to maintain the New Ratio 1 : 2 i.e, m : w :: 1 : 2 one should get Confused with initial mix i.e, 60Ltr.

Method of Substitution :
Already milk 40Ltr and water 20Ltr question is how much further or additional water is added to maintain the New Ratio 1 : 2.
We have [A]. 20 litres [B].30 litres [C].40 litres [D].60 litres.

Water should be 20 + either A,B,C,D but New Ratio 1 : 2 therefore w = 20 + 60 = 80 hence m:w = 40/80 = 1:2.

I hope you have understood the solution.

Hi, I am confused, please give me an easy way.

Can anyone explain it in an easy way?

Alligation.

Take ratio of milk.

2/3.0.

1/3.

1/3.1/3.

Assume x as the amount of water to be added.

Therefore 60/x = 1/3 * 3/1.

X = 60.

I don't understand this mixture method. Please help me to get this.

I can't able to understand the new ratio 1:2. Someone, please explain me.

Anyone tell me from where 2/3 come?

Thanks, @Ashok.