Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 2)
2.
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Answer: Option
Explanation:
Let the third number be x.
| Then, first number = 120% of x = | 120x | = | 6x |
| 100 | 5 |
| Second number = 150% of x = | 150x | = | 3x |
| 100 | 2 |
 Ratio of first two numbers = |
 |
6x | : | 3x |  |
= 12x : 15x = 4 : 5. |
| 5 | 2 |
Discussion:
134 comments Page 2 of 14.
Apeksha Puppalwar said:
1 year ago
Consider third number as X.
The question say's that 1st number is 20% more than the third number means a = 20%X + X.
Similarly,
Second number = b = 50%X + X,
a/b = 0.2X + X/0.5X + X,
= X(0.2 + 1)/X(0.5 + 1),
= 1.2/1.5.
= 4/5.
The question say's that 1st number is 20% more than the third number means a = 20%X + X.
Similarly,
Second number = b = 50%X + X,
a/b = 0.2X + X/0.5X + X,
= X(0.2 + 1)/X(0.5 + 1),
= 1.2/1.5.
= 4/5.
(7)
Niz said:
1 decade ago
If a, b, c.
a = c + 20% of c.
i.e a = c + 20/100*c.
a = c + 0.2 c.
i.e 1.2 c.
Also b = c + 50% of c.
i.e b = c + 50/100*c b = c + 0.5 c.
i.e 1.5 c.
Ratio between three numbers.
= 1.2 c : 1.5 c : c.
= 1.2 : 1.5.
i.e 4 : 5.
a = c + 20% of c.
i.e a = c + 20/100*c.
a = c + 0.2 c.
i.e 1.2 c.
Also b = c + 50% of c.
i.e b = c + 50/100*c b = c + 0.5 c.
i.e 1.5 c.
Ratio between three numbers.
= 1.2 c : 1.5 c : c.
= 1.2 : 1.5.
i.e 4 : 5.
Ravi said:
8 years ago
Simply, we all know that in Case Of percent 100 % is max percentage.
So take 3rd number be 100%
A say more than 3rd no. That is 20%+100%=120% or 1.2
B say more than 3rd no. That is 50%+100%=150% or 1.5
Now, divide A/B=1.2/1.5=4:5.
So take 3rd number be 100%
A say more than 3rd no. That is 20%+100%=120% or 1.2
B say more than 3rd no. That is 50%+100%=150% or 1.5
Now, divide A/B=1.2/1.5=4:5.
Juke said:
8 years ago
Here is my solution.
Let,
x be the first num.
y be the 2nd.
z be the 3rd.
x is larger than z by 20% so,
x=1.2z : z=x/1.2.
y is larger than z by 50% so.
y = 1.5z : z = y/1.5.
Equate z,
x/1.2 = y/1.5.
x/y = 1.2/1.5.
x/y = 4/5.
4:5.
Let,
x be the first num.
y be the 2nd.
z be the 3rd.
x is larger than z by 20% so,
x=1.2z : z=x/1.2.
y is larger than z by 50% so.
y = 1.5z : z = y/1.5.
Equate z,
x/1.2 = y/1.5.
x/y = 1.2/1.5.
x/y = 4/5.
4:5.
Giri said:
1 decade ago
Let x be 3rd number then,
1st number is 20% greater than 3rd number,so 1st number is equal to
x+(x*(20/100)).
x(1+(20/100)).
x((100+20)/100).
x*(120/100).
That why we will add 100 to given percentage to find increase in it.
1st number is 20% greater than 3rd number,so 1st number is equal to
x+(x*(20/100)).
x(1+(20/100)).
x((100+20)/100).
x*(120/100).
That why we will add 100 to given percentage to find increase in it.
Manas said:
10 years ago
Out of three number, the first number and the second number are respectively 25% and 30% less then the third number. By what percentage is the second number less then the first?
Can any one solve the problem? Then please.
Can any one solve the problem? Then please.
LOKESH ANAND said:
10 years ago
Let third number is 100.
Than 20% of third = 20 & 50% of third 50.
Than first number = 120(100+20).
Then second number = 150(100+50).
By question, Ratio of two number = First number:Second number.
= 120:150 = 4:5.
Than 20% of third = 20 & 50% of third 50.
Than first number = 120(100+20).
Then second number = 150(100+50).
By question, Ratio of two number = First number:Second number.
= 120:150 = 4:5.
Morepankh said:
4 years ago
ATP,
1st no., Is 20% more than 3rd no.
Let 3rd no., be x;
Then, 1st no.,=(20/100)*x+x.
2nd no.,=(50/100)*x+x.
Finally,
1st = 120x/100.
2nd = 150x/100.
3rd = x.
Ratio required = 120x/100:150x/100.
= 4:5.
1st no., Is 20% more than 3rd no.
Let 3rd no., be x;
Then, 1st no.,=(20/100)*x+x.
2nd no.,=(50/100)*x+x.
Finally,
1st = 120x/100.
2nd = 150x/100.
3rd = x.
Ratio required = 120x/100:150x/100.
= 4:5.
Satish rathnam said:
1 decade ago
ok mr.gitty take 'x' only. u will get 4:5
=>1st number :2nd number
=> 20% more than X : 50% more than X
=> now cancel "more than X" on both sides
=> 20% : 50 %
=> 1.2 : 1.5
=> 4:5
=>1st number :2nd number
=> 20% more than X : 50% more than X
=> now cancel "more than X" on both sides
=> 20% : 50 %
=> 1.2 : 1.5
=> 4:5
Sajal Das said:
1 decade ago
Let the 2 Nos are A and B and the 3rd No. is C.
According to the question A is 20% more than C. i.e., A=(1.2)C and B is 50% more than C. i.e., B=(1.5)C.
And so the ratio is {(1.2)C}/{(1.5)C} = 4/5 , i.e., 4:5.
According to the question A is 20% more than C. i.e., A=(1.2)C and B is 50% more than C. i.e., B=(1.5)C.
And so the ratio is {(1.2)C}/{(1.5)C} = 4/5 , i.e., 4:5.
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