Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = |  |
5 x | 3 |  |
: | |
8 x | 3 | |
= 3 : | 24 |
| 5 | 5 | 5 |
 A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
| B = |
|
98 x | 15 | |
= 30. |
| 49 |
Discussion:
122 comments Page 4 of 13.
Sweet said:
1 decade ago
Let a's amount= z
so b's amount=1210-z
now (4/15)z=(2/5)x(1210-z)
=>
(4/15)z=484-2/5z
=>
(4/15)z+(2/5)z=484
=>
by taking l.c.m (10/15)z=484
=> 10z=7260
=>
z=726
So a's amount=z=726
and b's amount=1210-726=484 ans.
so b's amount=1210-z
now (4/15)z=(2/5)x(1210-z)
=>
(4/15)z=484-2/5z
=>
(4/15)z+(2/5)z=484
=>
by taking l.c.m (10/15)z=484
=> 10z=7260
=>
z=726
So a's amount=z=726
and b's amount=1210-726=484 ans.
Chandan said:
1 decade ago
A:B = 2:3.
B:C = 5:8.
(2:3)x5 = 10:15.
(5:8)x3 = 15:24.
A:B:C = 10:15:24.
Let the ratio of numbers be 10x:15x:24x.
According to question,
10x+15x+24x = 98.
49x = 98.
x = 98/49.
x = 2.
Now 2nd number is 15x.
i.e;15*2 = 30.
B:C = 5:8.
(2:3)x5 = 10:15.
(5:8)x3 = 15:24.
A:B:C = 10:15:24.
Let the ratio of numbers be 10x:15x:24x.
According to question,
10x+15x+24x = 98.
49x = 98.
x = 98/49.
x = 2.
Now 2nd number is 15x.
i.e;15*2 = 30.
Swetha said:
4 years ago
To get ratio as f:s:t we make s ratio equal in both multiply first ratio with 5 and second ratio with 3 then you will get 10:15 and 15:24 now we can write 10:15:24 and on adding them the result is 98 and we get x=2 and s=2(15)=30.
(3)
Elizabeth Scaria said:
1 decade ago
If a:b=m:n and b:c=p:q then a:b:c= mp:np:nq.
Here,
a:b=2:3 .
b:c=5:8.
Then a:b:c become 10:15:24.
If sum of money S is divided in the ratio a:b:c then part of b is
= (b/a+b+c)*S.
Now here part of B become (15/49)*98 = 30.
Here,
a:b=2:3 .
b:c=5:8.
Then a:b:c become 10:15:24.
If sum of money S is divided in the ratio a:b:c then part of b is
= (b/a+b+c)*S.
Now here part of B become (15/49)*98 = 30.
Muhammad Usman Shoaib said:
10 years ago
If are is the remainder when a positive integer is divided by a single- digit prime integer, what is the largest possible value of are?
Options : A 6, B 7, C 8, D 9 and E : It cannot be determined from the information above.
Options : A 6, B 7, C 8, D 9 and E : It cannot be determined from the information above.
Vinni said:
1 decade ago
A:B = 2:3.
B:C = 5:8.
By short cut we get,
A:B:C = 10:15:24.
How we get is by using above ratios,
A's value = A*B.
B = B*B.
C = B*C...
Then as given in problem,
10x+15x+24x = 98.
49x = 98.
x = 2..
So, 15x = 15*2 = 30.
B:C = 5:8.
By short cut we get,
A:B:C = 10:15:24.
How we get is by using above ratios,
A's value = A*B.
B = B*B.
C = B*C...
Then as given in problem,
10x+15x+24x = 98.
49x = 98.
x = 2..
So, 15x = 15*2 = 30.
AJAY said:
9 years ago
A : B = 2 : 3
B : C = 5 : 8.
MAKE B EQUAL BY MUL WITH 5 AND 3.
5* 2 : 3 = 10 : 15
3* 5 : 8 = 15 : 24
CON
10:15:24
NOW 10X + 15 + 24 = 98;
X = 98/49;
FOR B
15 * 98/49 = 30 -> Answer.
B : C = 5 : 8.
MAKE B EQUAL BY MUL WITH 5 AND 3.
5* 2 : 3 = 10 : 15
3* 5 : 8 = 15 : 24
CON
10:15:24
NOW 10X + 15 + 24 = 98;
X = 98/49;
FOR B
15 * 98/49 = 30 -> Answer.
Nikesh Prasad said:
6 years ago
Given A:B = 2:3 and B:C = 5:8.
Our objective is to make the ratio of B same in both the given ratios so we multiply 5 with A:B and 3 with B:C.
B becomes 15 and we get the original ratio i.e., 10:15:24.
Our objective is to make the ratio of B same in both the given ratios so we multiply 5 with A:B and 3 with B:C.
B becomes 15 and we get the original ratio i.e., 10:15:24.
Prince said:
9 years ago
Of the three numbers, the ratio of first and second is 8:9 and that of second and third is 3:4. If the product of the third number is 2400, Find the second number?
Please help me to find the solution.
Please help me to find the solution.
Oronno said:
8 years ago
Let, first numbr=a.
2nd numbr=b.
3rd numbr=c.
Given that,
a:b=2:3
b:c=5:8
So,
a:b=2:3=5*2:5*3=10:15
b:c=5:8=3*5:3*8=15:24.
Then,
a:b:c=10:15:24 ( multiply by 2)
a:b:c=20:30:48.
Ans=30.
2nd numbr=b.
3rd numbr=c.
Given that,
a:b=2:3
b:c=5:8
So,
a:b=2:3=5*2:5*3=10:15
b:c=5:8=3*5:3*8=15:24.
Then,
a:b:c=10:15:24 ( multiply by 2)
a:b:c=20:30:48.
Ans=30.
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