Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = |  |
5 x | 3 |  |
: | |
8 x | 3 | |
= 3 : | 24 |
| 5 | 5 | 5 |
 A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
| B = |
|
98 x | 15 | |
= 30. |
| 49 |
Discussion:
122 comments Page 5 of 13.
Ashwin Patil said:
8 years ago
a:b=2:3
c:d=5:8
The rule is that from ration & proportion becomes
a:b
------------
ac:bc:bd
from rule
2:3
------------
2x5:3x5:3x8
2:3
-------
10:15:24
Second no. be 98 x 15/43= 30.
c:d=5:8
The rule is that from ration & proportion becomes
a:b
------------
ac:bc:bd
from rule
2:3
------------
2x5:3x5:3x8
2:3
-------
10:15:24
Second no. be 98 x 15/43= 30.
Ashok said:
7 years ago
a/b=2/3=>a=2/3*b.
b/c=5/8=>c/b=8/5=>c=8/5*b.
Given.
a+b+c=98.
2/3*b+b+8/5*b=98.
10b+15b+24b/15=98.
49b=98*15.
49b=49*2*15(98 has written as 49*2).
b=49*2*15/49.
b=15*2.
b=30.
b/c=5/8=>c/b=8/5=>c=8/5*b.
Given.
a+b+c=98.
2/3*b+b+8/5*b=98.
10b+15b+24b/15=98.
49b=98*15.
49b=49*2*15(98 has written as 49*2).
b=49*2*15/49.
b=15*2.
b=30.
SUJITH said:
6 years ago
It's very simple.
Given 2 : 3 and 5 : 8.
i.e;
2 3
| /|
|/ |
5 8
1st term a is-----> 2 * 5 = 10.
2nd term b is-----> 5 * 3 = 15.
3rd term c is------> 3 * 8 = 24.
then,
10:15:24.
Given 2 : 3 and 5 : 8.
i.e;
2 3
| /|
|/ |
5 8
1st term a is-----> 2 * 5 = 10.
2nd term b is-----> 5 * 3 = 15.
3rd term c is------> 3 * 8 = 24.
then,
10:15:24.
RAMESH said:
7 years ago
A + B + C = 98.
Divide L.H.S and R.H.S With B We get;
A/B+B/B+C/B = 98/B,
A/B+1+C/B = 98/B,
THEN We have A/B AND B/C=5/8 then C/B=8/5.
2/3+1+8/5=98/B,
SIMPLIFY WE GET B=30.
Divide L.H.S and R.H.S With B We get;
A/B+B/B+C/B = 98/B,
A/B+1+C/B = 98/B,
THEN We have A/B AND B/C=5/8 then C/B=8/5.
2/3+1+8/5=98/B,
SIMPLIFY WE GET B=30.
Hariharan said:
2 years ago
2x : 3x
5x : 8x
98 = (2x*5x) + (5x*3x) + (3x*8x).
98 = 10x + 15x + 24x.
98 = 49x.
x = 2.
Apply x, here
=10(2) + 15(2) + 24(2)
=20 : 30 : 48.
So, the answer is B=30.
5x : 8x
98 = (2x*5x) + (5x*3x) + (3x*8x).
98 = 10x + 15x + 24x.
98 = 49x.
x = 2.
Apply x, here
=10(2) + 15(2) + 24(2)
=20 : 30 : 48.
So, the answer is B=30.
(65)
MANDEEP SINGH said:
1 decade ago
A:B:C.
2:3.
5:8.
We get A:B:C.
A = 2X5 = 10;
B = 3X5 = 15;
C = 3X8 = 24;
A:B:C = 10:15:24.
10x+15x+24x = 98.
49x = 98.
x = 2.
So B's sum is: 15X2 = 30.
2:3.
5:8.
We get A:B:C.
A = 2X5 = 10;
B = 3X5 = 15;
C = 3X8 = 24;
A:B:C = 10:15:24.
10x+15x+24x = 98.
49x = 98.
x = 2.
So B's sum is: 15X2 = 30.
Manisha said:
5 years ago
Let the three numbers be x, y and z.
x : y : z
2 : 3
-----5 : 8.
= 10 : 15 : 24 (2*5 : 3*5 : 3*8).
= 10 + 15 + 24 = 49.
for B = 98 * 15/49,
=30.
x : y : z
2 : 3
-----5 : 8.
= 10 : 15 : 24 (2*5 : 3*5 : 3*8).
= 10 + 15 + 24 = 49.
for B = 98 * 15/49,
=30.
(2)
ADITYA JAIN said:
9 years ago
Let the three ratio be = A:B:C.
A:B = 2:3.
B:C = 5:8.
Now A:B:C = 10:15:24 (2*5 = 10, 3*5 = 15, 3*8 = 24).
Now 10 + 15 + 24 = 49.
B = 98 * 15/49.
= 30.
A:B = 2:3.
B:C = 5:8.
Now A:B:C = 10:15:24 (2*5 = 10, 3*5 = 15, 3*8 = 24).
Now 10 + 15 + 24 = 49.
B = 98 * 15/49.
= 30.
Uday said:
7 years ago
A+B+C=98
A:B=2:3
B:C=5:8
A:B:C=10:15:24
10X+15X+24X=98
then the valve of x = 2
Now, we need 2nd no then substitute the valve of x in B then 15*2=30.
A:B=2:3
B:C=5:8
A:B:C=10:15:24
10X+15X+24X=98
then the valve of x = 2
Now, we need 2nd no then substitute the valve of x in B then 15*2=30.
JAY NAMDEV said:
1 decade ago
There are 150 students in a class, we have only 58 rupees, if we distribute 25p and 50p amongst girls and boys respectively then what no of girls?
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