Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = |  |
5 x | 3 |  |
: | |
8 x | 3 | |
= 3 : | 24 |
| 5 | 5 | 5 |
 A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
| B = |
|
98 x | 15 | |
= 30. |
| 49 |
Discussion:
122 comments Page 3 of 13.
Emani Karthik Reddy said:
1 decade ago
Sum of numbers Ax+Bx+Cx=98->1
Ratio of first to second 2:3
second to third 5:8
the ratio A:B::C:D=2:3::5:8
find the ratio A:B:C
i.e A:B:C=2:3::(5*(3/5)):(8*(3/5)).
new ratio is 2:3::3:24/5
A:B:C=2:3:24/5
A:B:c=10:15:24
from 1 we get
10x+15x+24x=98
x=2
second number =15*2=30.
Ratio of first to second 2:3
second to third 5:8
the ratio A:B::C:D=2:3::5:8
find the ratio A:B:C
i.e A:B:C=2:3::(5*(3/5)):(8*(3/5)).
new ratio is 2:3::3:24/5
A:B:C=2:3:24/5
A:B:c=10:15:24
from 1 we get
10x+15x+24x=98
x=2
second number =15*2=30.
Nitika said:
5 years ago
a:b = 2:3,
C:d = 5:8,
a:b:c= 10:15:24.
And 10+15+24 = 49 but their total given is 98.
So, we will multiply 49 by 2(because. Their total is 98 not 49) which will be 98.
Now; as in question they have asked to find the second number. So we will now multiply 15 by 2 = 30 answer.
C:d = 5:8,
a:b:c= 10:15:24.
And 10+15+24 = 49 but their total given is 98.
So, we will multiply 49 by 2(because. Their total is 98 not 49) which will be 98.
Now; as in question they have asked to find the second number. So we will now multiply 15 by 2 = 30 answer.
(2)
Saurabh Kumar said:
5 years ago
@All.
Solution:
A: B = 2:3 and B: C = 5:8.
So Multiply A: B by 5 and B: C by 3.
So, we got a common B.
A: B = 10:15 and B: C = 15:24.
Total sum = 10+15+24 = 49,
Now, we want B so we simply.
B = (15/49)*Sum of total numbers (GIVEN).
B = (15/49)*98.
we get 30.
Solution:
A: B = 2:3 and B: C = 5:8.
So Multiply A: B by 5 and B: C by 3.
So, we got a common B.
A: B = 10:15 and B: C = 15:24.
Total sum = 10+15+24 = 49,
Now, we want B so we simply.
B = (15/49)*Sum of total numbers (GIVEN).
B = (15/49)*98.
we get 30.
Kalpa said:
1 decade ago
Let 3 number are X,Y,Z
given X+Y+Z=98
X:Y::2:3 Y:Z::5:8
=> X/Y=2/3 =>Y/Z=5/8
=> X=2Y/3 =>Z=8Y/5
so,X+y+z=98
=>2Y/3+y+8Y/5=98
=>(10Y+15Y=24Y)/15=98
=>Y=1470/49
=>Y=30
so,2nd no. is 30.
given X+Y+Z=98
X:Y::2:3 Y:Z::5:8
=> X/Y=2/3 =>Y/Z=5/8
=> X=2Y/3 =>Z=8Y/5
so,X+y+z=98
=>2Y/3+y+8Y/5=98
=>(10Y+15Y=24Y)/15=98
=>Y=1470/49
=>Y=30
so,2nd no. is 30.
Abhijith said:
1 decade ago
x+y+z = 98;--> eq.1
x/y = 2/3;
y/z = 5/8;
x = (2y/3);
z = (8y/5).
Substituting new value of x and z in eq 1,
=> (2y/3)+y+(8y/5)=98;
Taking LCM as 15;
=> (10y+15y+24y)/15=98;
=> 49y=98*15;
=> y=(98*15)/49;
=> y=2*15;
=> y=30.
x/y = 2/3;
y/z = 5/8;
x = (2y/3);
z = (8y/5).
Substituting new value of x and z in eq 1,
=> (2y/3)+y+(8y/5)=98;
Taking LCM as 15;
=> (10y+15y+24y)/15=98;
=> 49y=98*15;
=> y=(98*15)/49;
=> y=2*15;
=> y=30.
Ashok said:
4 years ago
Simple way.
A:B:C.
2:3:
:5:8.
Add same value adjacent to blank space.
i.e,
2:3:3,
5:5:8 and multiply,
10:15:24.
Total Sum = 98.
Total sum of ratio=49.
Divide = 98/49=2.
Multiply 2 * 15 = 30 Ans.
Here, 15 is ratio of the 2nd number which is to be find.
A:B:C.
2:3:
:5:8.
Add same value adjacent to blank space.
i.e,
2:3:3,
5:5:8 and multiply,
10:15:24.
Total Sum = 98.
Total sum of ratio=49.
Divide = 98/49=2.
Multiply 2 * 15 = 30 Ans.
Here, 15 is ratio of the 2nd number which is to be find.
(28)
RATHINAVEL M said:
2 years ago
A : B : C.
A:B = 2:3.
B:C = 5:8.
A:B:C = ?
A:B:C.
2:3:? (2:3:3 (nearest value))
?:5:8 (5(nearest value):5:8)
--------
10:15:24.
Add the value 10x + 15x + 24x = 98.
x = 2.
10(2) : 15(2) : 24(2).
20 : 30 : 48.
ANSWER : The second number is 30.
A:B = 2:3.
B:C = 5:8.
A:B:C = ?
A:B:C.
2:3:? (2:3:3 (nearest value))
?:5:8 (5(nearest value):5:8)
--------
10:15:24.
Add the value 10x + 15x + 24x = 98.
x = 2.
10(2) : 15(2) : 24(2).
20 : 30 : 48.
ANSWER : The second number is 30.
(79)
Kanchan said:
5 years ago
For making B in the ratio equal.
A:B =5*2:3*5
B:C = 3*5:8*3
A:B:C become,
10:15:24.
Now let multiple ratio by x.
10x:15x:24x.
As given;
10x + 15x + 24x = 98
49x = 98.
x = 2.
Now the second no.is 15x.
So, 15x2= 30.
Therefore the Correct answer is B.
A:B =5*2:3*5
B:C = 3*5:8*3
A:B:C become,
10:15:24.
Now let multiple ratio by x.
10x:15x:24x.
As given;
10x + 15x + 24x = 98
49x = 98.
x = 2.
Now the second no.is 15x.
So, 15x2= 30.
Therefore the Correct answer is B.
(3)
Sid said:
1 decade ago
@jay namdev we have Rs.58.
IN 58 25 paise is = 58*4 = 232.
In 58 50 paise is = 58*2 = 116.
Ratio of 50 paise : 25 paise 1:2.
Total 150 student it means if boys is 50 then girls is 100.
100+50 =150.
It means total girls in class is 100.
IN 58 25 paise is = 58*4 = 232.
In 58 50 paise is = 58*2 = 116.
Ratio of 50 paise : 25 paise 1:2.
Total 150 student it means if boys is 50 then girls is 100.
100+50 =150.
It means total girls in class is 100.
Kishore said:
7 months ago
2 : 3 : same as second (3).
same as second (5) : 5 : 8.
2*5 = 10 || 3*5 = 15 || 3*8 = 24,
Combined ratio: 10:15:24.
The Sum of ratios: 10+15+24 = 49.
Actual sum: 98.
Multiply by 2: 10×2=20, 15×2=30, 24×2=48.
Second number: 30.
same as second (5) : 5 : 8.
2*5 = 10 || 3*5 = 15 || 3*8 = 24,
Combined ratio: 10:15:24.
The Sum of ratios: 10+15+24 = 49.
Actual sum: 98.
Multiply by 2: 10×2=20, 15×2=30, 24×2=48.
Second number: 30.
(7)
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