Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 7)
7.
Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Answer: Option
Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
| Then, | 2x + 4000 | = | 40 |
| 3x + 4000 | 57 |
57(2x + 4000) = 40(3x + 4000)
6x = 68,000
3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
Discussion:
82 comments Page 2 of 9.
Akib ali said:
3 years ago
The easiest way is;
1st-17 * (2:3) then,
34 : 51.
After increment 40 : 57.
2nd step 40-34=6 & 57-51=6 (we multiply in 1st step for difference of both is equal).
3rd- increment is 4000 means 6part=4000, 1part = 2000/3.
Then after increment his salary = 57part = 57*2000/3= 19*2000= 38000.
And Ravi's salary = 40 * 2000/3 = 26666.66.
1st-17 * (2:3) then,
34 : 51.
After increment 40 : 57.
2nd step 40-34=6 & 57-51=6 (we multiply in 1st step for difference of both is equal).
3rd- increment is 4000 means 6part=4000, 1part = 2000/3.
Then after increment his salary = 57part = 57*2000/3= 19*2000= 38000.
And Ravi's salary = 40 * 2000/3 = 26666.66.
(15)
Ruchith praharsha said:
7 years ago
The original ratio of their salaries are 2:3 and they are increased by 4000 the new ratio is 40:57.
Let their salaries be 2x ,3x.
2x+4000:3x+4000 = 40 :57,
114x +228000 =120x +160000,
6x =68000,
3x =34000 sumits original salary is 34000,
And after increase his salary =34000 + 4000= 38000.
Let their salaries be 2x ,3x.
2x+4000:3x+4000 = 40 :57,
114x +228000 =120x +160000,
6x =68000,
3x =34000 sumits original salary is 34000,
And after increase his salary =34000 + 4000= 38000.
(2)
Satish Konakalla said:
10 months ago
Old Ratio = 2:3.
New ratio = 40:57.
The change in salary is 4000.
Formula = the difference between (2, 3 = 1) * (40:57) = 40 : 57.
The difference between (40, 57 = 7 ) *(2:3) = 34 : 51.
34 : 51
40 : 57.
6 parts difference (34~40, 51~57) = 4000/-
Then 57 parts(Sumit's salary) = 57*(4000/6).
= 38000.
New ratio = 40:57.
The change in salary is 4000.
Formula = the difference between (2, 3 = 1) * (40:57) = 40 : 57.
The difference between (40, 57 = 7 ) *(2:3) = 34 : 51.
34 : 51
40 : 57.
6 parts difference (34~40, 51~57) = 4000/-
Then 57 parts(Sumit's salary) = 57*(4000/6).
= 38000.
(19)
Divya said:
1 decade ago
@Shikha.
Its just the new ratio. Read the question again and look at the 1st explanation til the 3rd step.
After that just divide 68000 by 6. You will get 33999 and it rounded of to 34000.
34000+4000 = 38000 which means 34000 was his old salary and aft increment of 4000 he gets 38000.
Its just the new ratio. Read the question again and look at the 1st explanation til the 3rd step.
After that just divide 68000 by 6. You will get 33999 and it rounded of to 34000.
34000+4000 = 38000 which means 34000 was his old salary and aft increment of 4000 he gets 38000.
Pranshu said:
5 years ago
57 - 40 = 17.
Then after.
57multiple with 4000 = 228000.
And then 40 multiple with = 160000.
Then substrate 228000-160000 = 68000.
Then 2x multiple 3x so 6x.
6x = 68000.
2x into 3x = 68000.
3x = 34000.
And then 3x+ 4000.
So 34000 + 4000 = 38000.
Then after.
57multiple with 4000 = 228000.
And then 40 multiple with = 160000.
Then substrate 228000-160000 = 68000.
Then 2x multiple 3x so 6x.
6x = 68000.
2x into 3x = 68000.
3x = 34000.
And then 3x+ 4000.
So 34000 + 4000 = 38000.
(2)
Shobha said:
1 decade ago
I have one doubt related to this type of question, here they mentioned the salary amount, if salary amount is mentioned in percentage how should we calculate.
Example salary is increased 20 % each. How should we calculate.
Any one can guide me?
Example salary is increased 20 % each. How should we calculate.
Any one can guide me?
S.Narayana said:
8 years ago
The shortcut formulae for these kinds of sums = (difference of new ratio/cross difference of both ratios )*increased value * require value.
= (57-40/120-114) * 4000 * 3.
= 17/6 * 12000.
=34000 =34000 + 4000(given in the question).
= (57-40/120-114) * 4000 * 3.
= 17/6 * 12000.
=34000 =34000 + 4000(given in the question).
VISHAL said:
7 years ago
#Shortest solution#
Ravi's old salary =2p,
Sumit's old salary=3p,
Ravi's new salary =40q,
Sumit's new salary=57q.
40q -2p=4000 ---> 1
57q-3p=4000 ---> 2
On solving [1] &[2] we get q=2000/3,
So sumit's new salary is 57 * (2000/3)=3800.
Ravi's old salary =2p,
Sumit's old salary=3p,
Ravi's new salary =40q,
Sumit's new salary=57q.
40q -2p=4000 ---> 1
57q-3p=4000 ---> 2
On solving [1] &[2] we get q=2000/3,
So sumit's new salary is 57 * (2000/3)=3800.
Gopal said:
6 years ago
The ratio of students in class A and class B is 4:5. The ratio of the fee collected per student from class A and class B is 25:16. If the total fee collected is 81 lakh, what is the fee collected from class B. Can anyone solve this?
Kumari said:
10 years ago
Why every one is taking this new ratio as 40/57 there may be a multiple for this i.e 40y/57y, here y is the multiple number other then x, can any one explain me about this, while doing cross multiplication it is important I think.
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