Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 7)
7.
Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Answer: Option
Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
| Then, | 2x + 4000 | = | 40 |
| 3x + 4000 | 57 |
57(2x + 4000) = 40(3x + 4000)
6x = 68,000
3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
Discussion:
82 comments Page 1 of 9.
Shanti said:
1 decade ago
How 6x=68000 and 3x=34000? please explain cleraly.
Aparna said:
1 decade ago
Just they have splitted the term
6x=68000
we can also write it as
2*3x=68000
3x=68000/2
therefore,
3x=34000
for the simplication they have done this
6x=68000
we can also write it as
2*3x=68000
3x=68000/2
therefore,
3x=34000
for the simplication they have done this
Emani karthik Reddy said:
1 decade ago
Let the salaries of ravi&sumith 2x,3x
each salary increased by 4000.
i.e ((2x+4000)/(3x+4000))->1
new ratio is 40:57->2
from 1 &2 we get
6x=68000
3x=34000
salary of sumith = 34000+4000=38000
each salary increased by 4000.
i.e ((2x+4000)/(3x+4000))->1
new ratio is 40:57->2
from 1 &2 we get
6x=68000
3x=34000
salary of sumith = 34000+4000=38000
Aman said:
1 decade ago
Any other method which solve this question in mind?
Prapu said:
1 decade ago
I did't understand clearly please explain this solution in an understandable manner.
Elumalai said:
1 decade ago
Hai guys listen here...
the 2:3 ratio of Ravi & Sumith salary
2x:3x =>2x/3x
then
Salary increased by each 4000
2x+4000 ---------(1)
3x+4000----------(2)
let we write 2x+4000/3x+4000 (its become new ratio)
2x+4000/3x/4000=40/57 ratio
now solve this
57(2x+4000)=40(3x+4000)
114x+228000=120x+160000
114x-120x=228000-160000
6x=68000
now divided by 2
=> 3x=34000.
now we have 3x value is 34000
let subsitute equation no(2)
=>3x+4000
=>34000+4000
Ans =38000
ok bye...
the 2:3 ratio of Ravi & Sumith salary
2x:3x =>2x/3x
then
Salary increased by each 4000
2x+4000 ---------(1)
3x+4000----------(2)
let we write 2x+4000/3x+4000 (its become new ratio)
2x+4000/3x/4000=40/57 ratio
now solve this
57(2x+4000)=40(3x+4000)
114x+228000=120x+160000
114x-120x=228000-160000
6x=68000
now divided by 2
=> 3x=34000.
now we have 3x value is 34000
let subsitute equation no(2)
=>3x+4000
=>34000+4000
Ans =38000
ok bye...
(7)
Manish tiwari said:
1 decade ago
Thanks dear good explanation by Elumalai.
Jancy said:
1 decade ago
Thanks good explanation elumalai
Kauthik said:
1 decade ago
From the beginning itself, the increased salary of both of them were added. i.e., 2x+4000/3x+4000.
My question is after finding the value of x, why they add again by 4000. Can you please clear it.
My question is after finding the value of x, why they add again by 4000. Can you please clear it.
Sowmi said:
1 decade ago
Sumit ratio is 3x.
His salary increased by 4000. So current salary is 3x+4000->equation 1.
We found out 3x=34000.
So substitute 3x=34000 in equation 1. So 34000+4000=38000.
His salary increased by 4000. So current salary is 3x+4000->equation 1.
We found out 3x=34000.
So substitute 3x=34000 in equation 1. So 34000+4000=38000.
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