Aptitude - Ratio and Proportion - Discussion

@All.

The question makes no sense. Because both of their salaries might not be the same, it can be different. How come we put x both in their salaries?

Anyone, please explain to me.

Let the salaries of Ravi and Sumit be and, respectively.
After increasing each salary by Rs. 4000, the new salaries become:

Ravi's new salary:
Sumit's new salary:


The ratio of their new salaries is given as . Therefore, we can write the equation:
frac{2x + 4000}{3x + 4000} = frac{40}{57}

Cross-multiply to eliminate the fraction:
57(2x + 4000) = 40(3x + 4000)

Expand both sides:
114x + 228000 = 120x + 160000

Simplify the equation:
228000 - 160000 = 120x - 114x
68000 = 6x

Solve for :
x = frac{68000}{6} = 11333.33
Sumit's original salary is :
3x = 3 times 11333.33 = 34000

Sumit's new salary:
3x + 4000 = 34000 + 4000 = 38000
Thus, Sumit's salary is Rs. 38,000.

Let's denote Ravi's initial salary as 2x and Sumit's as 3x.

After the increase, their salaries become:
* Ravi: 2x + 4000
* Sumit: 3x + 4000

The new ratio is 40:57, so we can set up the following equation:
(2x + 4000)/(3x + 4000) = 40/57.

Cross-multiplying:
57(2x + 4000) = 40(3x + 4000)
Expanding:
114x + 228000 = 120x + 160000.

Simplifying:
6x = 68000.

Solving for x:
x = 11333.33.

Now, Sumit's initial salary was 3x. So, his initial salary is:
3 * 11333.33 = 34000
After the increase of Rs. 4000, Sumit's salary becomes:
34000 + 4000 = 38000
Therefore, Sumit's salary is Rs. 38,000.

Old Ratio = 2:3.
New ratio = 40:57.
The change in salary is 4000.

Formula = the difference between (2, 3 = 1) * (40:57) = 40 : 57.
The difference between (40, 57 = 7 ) *(2:3) = 34 : 51.

34 : 51
40 : 57.

6 parts difference (34~40, 51~57) = 4000/-
Then 57 parts(Sumit's salary) = 57*(4000/6).
= 38000.

2X + 4000/3X + 4000 = 40/57.
114X + 228000 = 120X + 160000.
120X - 114X = 228000 - 160000.
6X = 68000.

So, both are divided by 2.
3X = 34000.
Put the value of 3X.
34000 + 4000 = 38000.

First ratio 2 : 3.
New ratio 40 : 57.
Increased in each 4000 4000.
Cross multiple each other.
40 × 3-57 × 2 = 57 × 4000-40 × 4000.
120 - 114 = 228000 - 160000
6 = 68000
1 = 666.

Sumit new 57×666. = 38000.

The answer of this question should be 34000 not 38000.

114x+4000*57=120x+4000*40.

6x = 4000(57-40),
6x = 4000*17,
x = (4000*17)/6,

Now you want to Sumit salary which is 3x in the above question.
3* (4000*17)/6 = 34000=> answer.

Here 6x=68000.

Then
Why don't you do
X=68000/6?
Didn't understand, plz explain the above step in detail.

2x + 4000 = 40 ---> (1)
3x + 4000 = 57 ---> (2)

Now, multiply 2x + 4000 by 3 and 3x + 4000 by 2.

6x + 12000 = 120 ---> (3)
6x + 8000 = 114 ---> (4)

Now, subtract (4) from (3)
We get, 4000 = 6.

Now, we are asked to find Sumit's new salary.
We know, the ratio of new salaries of Ravi and Sumit is 40:57
Therefore, 4000 * 57/ 6 = 38000.

Sumit's new salary is RS. 38000.