Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 7)
7.
Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Answer: Option
Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
| Then, | 2x + 4000 | = | 40 |
| 3x + 4000 | 57 |
57(2x + 4000) = 40(3x + 4000)
6x = 68,000
3x = 34,000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.
Discussion:
82 comments Page 2 of 9.
Varsha said:
3 years ago
How we get 2x+4000/3x+4000 = 47/50?
and why not 2x+4000/3x+4000 = 47x/50x?
and why not 2x+4000/3x+4000 = 47x/50x?
(8)
Akib ali said:
3 years ago
The easiest way is;
1st-17 * (2:3) then,
34 : 51.
After increment 40 : 57.
2nd step 40-34=6 & 57-51=6 (we multiply in 1st step for difference of both is equal).
3rd- increment is 4000 means 6part=4000, 1part = 2000/3.
Then after increment his salary = 57part = 57*2000/3= 19*2000= 38000.
And Ravi's salary = 40 * 2000/3 = 26666.66.
1st-17 * (2:3) then,
34 : 51.
After increment 40 : 57.
2nd step 40-34=6 & 57-51=6 (we multiply in 1st step for difference of both is equal).
3rd- increment is 4000 means 6part=4000, 1part = 2000/3.
Then after increment his salary = 57part = 57*2000/3= 19*2000= 38000.
And Ravi's salary = 40 * 2000/3 = 26666.66.
(15)
Ramya said:
3 years ago
Then what is the Salary of Ravi?
(5)
Athika said:
3 years ago
It is stated in question 'if' the salary is increased but it is not actually increased now at present how at the last point you have added 3x+4000?
Anyone, explain please.
Anyone, explain please.
Ranjan said:
4 years ago
R/S = 2/3.
(R+4000) / (S+4000) = 40/57.
Putting the value of are = (2/3) S,
And get value s = 34000.
What is wrong in this? Please explain it.
(R+4000) / (S+4000) = 40/57.
Putting the value of are = (2/3) S,
And get value s = 34000.
What is wrong in this? Please explain it.
(2)
Ashwin said:
4 years ago
Thank you @Elumalai.
Niranjan Katakam said:
4 years ago
Shortcut:
The first difference of new ration is 17.
So, 34:51, 40:57,
Both ratio difference is 6.
6p=4000 than 51p=?
Answer is 34000. Now add given increased 4000.
So, 34000 + 4000 = 38000.
The first difference of new ration is 17.
So, 34:51, 40:57,
Both ratio difference is 6.
6p=4000 than 51p=?
Answer is 34000. Now add given increased 4000.
So, 34000 + 4000 = 38000.
(7)
Pranshu said:
5 years ago
57 - 40 = 17.
Then after.
57multiple with 4000 = 228000.
And then 40 multiple with = 160000.
Then substrate 228000-160000 = 68000.
Then 2x multiple 3x so 6x.
6x = 68000.
2x into 3x = 68000.
3x = 34000.
And then 3x+ 4000.
So 34000 + 4000 = 38000.
Then after.
57multiple with 4000 = 228000.
And then 40 multiple with = 160000.
Then substrate 228000-160000 = 68000.
Then 2x multiple 3x so 6x.
6x = 68000.
2x into 3x = 68000.
3x = 34000.
And then 3x+ 4000.
So 34000 + 4000 = 38000.
(2)
Mohamed Rafiudeen said:
5 years ago
2:3 difference is 1.
40:57 difference is 17.
Cross multiply:
{2:3 * 17} 34:51.
{40:57 * 1}40:57.
Then difference of 2 ratios is 6.
6=57*4000,
6=228000,
228000÷6,
38,000.
40:57 difference is 17.
Cross multiply:
{2:3 * 17} 34:51.
{40:57 * 1}40:57.
Then difference of 2 ratios is 6.
6=57*4000,
6=228000,
228000÷6,
38,000.
(4)
Vamsi said:
5 years ago
Yes, it has another method.
2:3
40:57 -> difference = 17.
Cross multiply it,
(17/6)*4000*3=34000.
Total=34000+4000=38000.
114:120 ->difference = 6.
2:3
40:57 -> difference = 17.
Cross multiply it,
(17/6)*4000*3=34000.
Total=34000+4000=38000.
114:120 ->difference = 6.
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