Aptitude - Ratio and Proportion - Discussion

Let's denote Ravi's initial salary as 2x and Sumit's as 3x.

After the increase, their salaries become:
* Ravi: 2x + 4000
* Sumit: 3x + 4000

The new ratio is 40:57, so we can set up the following equation:
(2x + 4000)/(3x + 4000) = 40/57.

Cross-multiplying:
57(2x + 4000) = 40(3x + 4000)
Expanding:
114x + 228000 = 120x + 160000.

Simplifying:
6x = 68000.

Solving for x:
x = 11333.33.

Now, Sumit's initial salary was 3x. So, his initial salary is:
3 * 11333.33 = 34000
After the increase of Rs. 4000, Sumit's salary becomes:
34000 + 4000 = 38000
Therefore, Sumit's salary is Rs. 38,000.

Let the salaries of Ravi and Sumit be and, respectively.
After increasing each salary by Rs. 4000, the new salaries become:

Ravi's new salary:
Sumit's new salary:


The ratio of their new salaries is given as . Therefore, we can write the equation:
frac{2x + 4000}{3x + 4000} = frac{40}{57}

Cross-multiply to eliminate the fraction:
57(2x + 4000) = 40(3x + 4000)

Expand both sides:
114x + 228000 = 120x + 160000

Simplify the equation:
228000 - 160000 = 120x - 114x
68000 = 6x

Solve for :
x = frac{68000}{6} = 11333.33
Sumit's original salary is :
3x = 3 times 11333.33 = 34000

Sumit's new salary:
3x + 4000 = 34000 + 4000 = 38000
Thus, Sumit's salary is Rs. 38,000.

@All.

The question makes no sense. Because both of their salaries might not be the same, it can be different. How come we put x both in their salaries?

Anyone, please explain to me.