Aptitude - Ratio and Proportion - Discussion

Hai guys listen here...

the 2:3 ratio of Ravi & Sumith salary
2x:3x =>2x/3x
then
Salary increased by each 4000
2x+4000 ---------(1)
3x+4000----------(2)
let we write 2x+4000/3x+4000 (its become new ratio)
2x+4000/3x/4000=40/57 ratio
now solve this
57(2x+4000)=40(3x+4000)
114x+228000=120x+160000
114x-120x=228000-160000
6x=68000
now divided by 2
=> 3x=34000.

now we have 3x value is 34000
let subsitute equation no(2)
=>3x+4000
=>34000+4000
Ans =38000

ok bye...

How come 6x=68000?

Can you explain in detail?

Shortcut:

The first difference of new ration is 17.

So, 34:51, 40:57,
Both ratio difference is 6.
6p=4000 than 51p=?
Answer is 34000. Now add given increased 4000.
So, 34000 + 4000 = 38000.

Let's denote Ravi's initial salary as 2x and Sumit's as 3x.

After the increase, their salaries become:
* Ravi: 2x + 4000
* Sumit: 3x + 4000

The new ratio is 40:57, so we can set up the following equation:
(2x + 4000)/(3x + 4000) = 40/57.

Cross-multiplying:
57(2x + 4000) = 40(3x + 4000)
Expanding:
114x + 228000 = 120x + 160000.

Simplifying:
6x = 68000.

Solving for x:
x = 11333.33.

Now, Sumit's initial salary was 3x. So, his initial salary is:
3 * 11333.33 = 34000
After the increase of Rs. 4000, Sumit's salary becomes:
34000 + 4000 = 38000
Therefore, Sumit's salary is Rs. 38,000.

Then what is the Salary of Ravi?

2:3 difference is 1.

40:57 difference is 17.

Cross multiply:
{2:3 * 17} 34:51.
{40:57 * 1}40:57.
Then difference of 2 ratios is 6.
6=57*4000,
6=228000,
228000÷6,
38,000.

R/S = 2/3.

(R+4000) / (S+4000) = 40/57.
Putting the value of are = (2/3) S,
And get value s = 34000.

What is wrong in this? Please explain it.

57 - 40 = 17.

Then after.

57multiple with 4000 = 228000.
And then 40 multiple with = 160000.
Then substrate 228000-160000 = 68000.
Then 2x multiple 3x so 6x.
6x = 68000.
2x into 3x = 68000.
3x = 34000.
And then 3x+ 4000.
So 34000 + 4000 = 38000.

The original ratio of their salaries are 2:3 and they are increased by 4000 the new ratio is 40:57.

Let their salaries be 2x ,3x.
2x+4000:3x+4000 = 40 :57,
114x +228000 =120x +160000,
6x =68000,
3x =34000 sumits original salary is 34000,
And after increase his salary =34000 + 4000= 38000.

Hello friends,

Already this sum answer is given,
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then, 2x + 4000 = 40.
3x + 4000 = 57,
Till here you public know from where this come,
After that 6x = 68000, this is little bit question to us. From where this we got.

Here is the answer.

Across multiple,
57 (2x + 4000) =40 (3x + 4000).
2 * 3x = 6x, 57 - 40 = 17, 4000 is common.
6x = 17 * 4000.
6x = 68000. Here we solve sum doubt.

Going forward, we have to find Sumit salary.
6x = 68000 divide two as per the given ratio.
3x = 34000.

So here we got the value of 3x = 34000.

Sumit salary is 3x + 4000.
Therefore, 3x = 34000 + 4000.
Answer is 38000 Rs.