Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 15)
15.
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
| Then, sum of their values = Rs. |  |
25x | + | 10 x 2x | + | 5 x 3x |  |
= Rs. | 60x |
| 100 | 100 | 100 | 100 |
 |
60x | = 30 |  x = |
30 x 100 | = 50. |
| 100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
Discussion:
121 comments Page 3 of 13.
Raju said:
7 years ago
1 Rs = 100 praise
25p,10p,5p.
Ratio = 1:2:3.
Then 25*x + 10*2x + 5*3x = 30*100.
25x + 20x + 15x = 3000.
60x = 3000.
X = 3000/60.
X = 50.
25p,10p,5p.
Ratio = 1:2:3.
Then 25*x + 10*2x + 5*3x = 30*100.
25x + 20x + 15x = 3000.
60x = 3000.
X = 3000/60.
X = 50.
(1)
GuruVardhan said:
6 years ago
Let 30rs = 300p.
So 1x+2x+3x = 300.
x = 50.
So 1x:2x:3x = 50:100:150.
Ans is 150.
So 1x+2x+3x = 300.
x = 50.
So 1x:2x:3x = 50:100:150.
Ans is 150.
(1)
MANU said:
6 years ago
Ratio in amount in paisa 25:20:15.
No.of 5 paisa coins = (15x3000)/(60x5).
= 150 coins.
No.of 5 paisa coins = (15x3000)/(60x5).
= 150 coins.
(1)
Yhtsawakeviv said:
6 years ago
We can simply write;
1/4x + 1/10 * 2x + 1/20 * 3x = 30
Then after multiplying and taking LCM.
5x + 4x + 3x = 30 * 20,
x = 600/12,
x = 50.
So, No. of 5p coins = 3x = 3*50 = 150.
1/4x + 1/10 * 2x + 1/20 * 3x = 30
Then after multiplying and taking LCM.
5x + 4x + 3x = 30 * 20,
x = 600/12,
x = 50.
So, No. of 5p coins = 3x = 3*50 = 150.
(1)
Nitesh said:
2 decades ago
@ Nithyanantham.
Totally wrong, what you think it is not matter, matter is that what is written in question paper and another thing is that I've not seen this technique in mathematics may be this is advanced technique.
Totally wrong, what you think it is not matter, matter is that what is written in question paper and another thing is that I've not seen this technique in mathematics may be this is advanced technique.
Aparna said:
2 decades ago
Whenever we perform any calculations
first of all it should be converted into same units
here,
1Rs.=100ps
? =25ps
we get 25/100
first of all it should be converted into same units
here,
1Rs.=100ps
? =25ps
we get 25/100
Srj said:
2 decades ago
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
25p of x,10p of 2x,5p of 3x;
25p=25/100=1/4;
10p=10/100=1/10;
5p=5/100=1/20;
1x/4 + 2x/10 + 3x/20=30;
5x+4x+3x=600;
12x=600 (3*50)
x=150
25p of x,10p of 2x,5p of 3x;
25p=25/100=1/4;
10p=10/100=1/10;
5p=5/100=1/20;
1x/4 + 2x/10 + 3x/20=30;
5x+4x+3x=600;
12x=600 (3*50)
x=150
Habib said:
2 decades ago
I think in the ques it should be 15rs then the answer is correct !
For 30Rs one shud note that 5p coins should be maximum than any other coins (25p & 10ps) since the ratio of coins is 1:2:3.
If 150 coins had to be the answer. Then 25p & 10p shud be lesser than this... which will not in anycase amount to 30rs.
For 30Rs one shud note that 5p coins should be maximum than any other coins (25p & 10ps) since the ratio of coins is 1:2:3.
If 150 coins had to be the answer. Then 25p & 10p shud be lesser than this... which will not in anycase amount to 30rs.
AKSHAY said:
1 decade ago
SRJ: you have done some thing wrong as in oyur solution 'x=150'
but that is the no. of 25p coins!!!
but that is the no. of 25p coins!!!
Divyanshu said:
1 decade ago
Its Simple
Totally we have Rs.30 = 3000p
25p,10p, 5p are in ratio of 1:2:3 (given)
We can also write it as
No. of coins of 25p = x
No. of coins of 10p = 2x
No. of coins of 5p = 3x
then,
25(x)+10(2x)+5(3x)= 3000
we will find x = 50
No. of coins of 5p = 3*50 = 150
Totally we have Rs.30 = 3000p
25p,10p, 5p are in ratio of 1:2:3 (given)
We can also write it as
No. of coins of 25p = x
No. of coins of 10p = 2x
No. of coins of 5p = 3x
then,
25(x)+10(2x)+5(3x)= 3000
we will find x = 50
No. of coins of 5p = 3*50 = 150
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