Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 15)
15.
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
| Then, sum of their values = Rs. |  |
25x | + | 10 x 2x | + | 5 x 3x |  |
= Rs. | 60x |
| 100 | 100 | 100 | 100 |
 |
60x | = 30 |  x = |
30 x 100 | = 50. |
| 100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
Discussion:
122 comments Page 3 of 13.
AbhayM said:
1 decade ago
Shortcut:
Let us assume that there is only 25 paise coin, which implies there are 2 10 paise coins, 3 5 paise coins.
The total value adds upto:
1*25+2*10+3*5 = 60 paise.
But total we have 3000 paise.
So 3000/60 = 50.
So multiplying 50*3 we get 150 coins of 10 paise.
Let us assume that there is only 25 paise coin, which implies there are 2 10 paise coins, 3 5 paise coins.
The total value adds upto:
1*25+2*10+3*5 = 60 paise.
But total we have 3000 paise.
So 3000/60 = 50.
So multiplying 50*3 we get 150 coins of 10 paise.
(1)
Sutha said:
10 years ago
Q1)-A bag contains 1-rupee , 50 paise and 25 paise coins in the ratio 8 : 5 :3. If the total amount of money in the box is Rs 112.50 , the number of 50 paise coins is?
Answer the question.
Answer the question.
(1)
Raju said:
7 years ago
1 Rs = 100 praise
25p,10p,5p.
Ratio = 1:2:3.
Then 25*x + 10*2x + 5*3x = 30*100.
25x + 20x + 15x = 3000.
60x = 3000.
X = 3000/60.
X = 50.
25p,10p,5p.
Ratio = 1:2:3.
Then 25*x + 10*2x + 5*3x = 30*100.
25x + 20x + 15x = 3000.
60x = 3000.
X = 3000/60.
X = 50.
(1)
GuruVardhan said:
7 years ago
Let 30rs = 300p.
So 1x+2x+3x = 300.
x = 50.
So 1x:2x:3x = 50:100:150.
Ans is 150.
So 1x+2x+3x = 300.
x = 50.
So 1x:2x:3x = 50:100:150.
Ans is 150.
(1)
MANU said:
7 years ago
Ratio in amount in paisa 25:20:15.
No.of 5 paisa coins = (15x3000)/(60x5).
= 150 coins.
No.of 5 paisa coins = (15x3000)/(60x5).
= 150 coins.
(1)
Yhtsawakeviv said:
6 years ago
We can simply write;
1/4x + 1/10 * 2x + 1/20 * 3x = 30
Then after multiplying and taking LCM.
5x + 4x + 3x = 30 * 20,
x = 600/12,
x = 50.
So, No. of 5p coins = 3x = 3*50 = 150.
1/4x + 1/10 * 2x + 1/20 * 3x = 30
Then after multiplying and taking LCM.
5x + 4x + 3x = 30 * 20,
x = 600/12,
x = 50.
So, No. of 5p coins = 3x = 3*50 = 150.
(1)
Nitesh said:
2 decades ago
@ Nithyanantham.
Totally wrong, what you think it is not matter, matter is that what is written in question paper and another thing is that I've not seen this technique in mathematics may be this is advanced technique.
Totally wrong, what you think it is not matter, matter is that what is written in question paper and another thing is that I've not seen this technique in mathematics may be this is advanced technique.
Aparna said:
2 decades ago
Whenever we perform any calculations
first of all it should be converted into same units
here,
1Rs.=100ps
? =25ps
we get 25/100
first of all it should be converted into same units
here,
1Rs.=100ps
? =25ps
we get 25/100
Srj said:
2 decades ago
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
25p of x,10p of 2x,5p of 3x;
25p=25/100=1/4;
10p=10/100=1/10;
5p=5/100=1/20;
1x/4 + 2x/10 + 3x/20=30;
5x+4x+3x=600;
12x=600 (3*50)
x=150
25p of x,10p of 2x,5p of 3x;
25p=25/100=1/4;
10p=10/100=1/10;
5p=5/100=1/20;
1x/4 + 2x/10 + 3x/20=30;
5x+4x+3x=600;
12x=600 (3*50)
x=150
Habib said:
2 decades ago
I think in the ques it should be 15rs then the answer is correct !
For 30Rs one shud note that 5p coins should be maximum than any other coins (25p & 10ps) since the ratio of coins is 1:2:3.
If 150 coins had to be the answer. Then 25p & 10p shud be lesser than this... which will not in anycase amount to 30rs.
For 30Rs one shud note that 5p coins should be maximum than any other coins (25p & 10ps) since the ratio of coins is 1:2:3.
If 150 coins had to be the answer. Then 25p & 10p shud be lesser than this... which will not in anycase amount to 30rs.
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