Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 15)
15.
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs. | ![]() |
25x | + | 10 x 2x | + | 5 x 3x | ![]() |
= Rs. | 60x |
100 | 100 | 100 | 100 |
![]() |
60x | = 30 | ![]() |
30 x 100 | = 50. |
100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
Discussion:
117 comments Page 10 of 12.
Remi said:
7 years ago
1 Rupee = 100 paise
30Rs = 3000 paise.
25p : 10p : 5p = 1 : 2 : 3,
25*X + 10*2X + 5*3X = 3000,
60X = 3000,
X = 50,
25*50 = 1250,
10*2*50 = 1000,
5*3*50 = 750.
30Rs = 3000 paise.
25p : 10p : 5p = 1 : 2 : 3,
25*X + 10*2X + 5*3X = 3000,
60X = 3000,
X = 50,
25*50 = 1250,
10*2*50 = 1000,
5*3*50 = 750.
Bratish said:
7 years ago
25 paisa=1/4 rupee.
10 paisa=1/10 rupee.
5 paisa=1/20 rupee.
Assume that;
x/4:2x/10:3x/20.
then simplify ratio.
5x:4x:3x.
Then;
5x+4x+3x=30.
x=30/12;
So 3x rupees means
(30/12)*3=7.5;
and 5 paisa means
7.5*20=150.
10 paisa=1/10 rupee.
5 paisa=1/20 rupee.
Assume that;
x/4:2x/10:3x/20.
then simplify ratio.
5x:4x:3x.
Then;
5x+4x+3x=30.
x=30/12;
So 3x rupees means
(30/12)*3=7.5;
and 5 paisa means
7.5*20=150.
(1)
Raju said:
6 years ago
1 Rs = 100 praise
25p,10p,5p.
Ratio = 1:2:3.
Then 25*x + 10*2x + 5*3x = 30*100.
25x + 20x + 15x = 3000.
60x = 3000.
X = 3000/60.
X = 50.
25p,10p,5p.
Ratio = 1:2:3.
Then 25*x + 10*2x + 5*3x = 30*100.
25x + 20x + 15x = 3000.
60x = 3000.
X = 3000/60.
X = 50.
(1)
Akshayjr. said:
6 years ago
1x+2x+3x = 30.
6x = 30,
x=5.
Let;
1) 25 paise =Rs 1x5 =5 and No. Of coins = 5 * 4=20coins.
2) 10 paise =Rs 2x = 2 * 5 =Rs10 and no.of coins equal to 10 * 10 = 100 coins,
3) 5 paise= Rs 3x= 3x5=Rs15 and of coins =20 * 15= 300 coins.
6x = 30,
x=5.
Let;
1) 25 paise =Rs 1x5 =5 and No. Of coins = 5 * 4=20coins.
2) 10 paise =Rs 2x = 2 * 5 =Rs10 and no.of coins equal to 10 * 10 = 100 coins,
3) 5 paise= Rs 3x= 3x5=Rs15 and of coins =20 * 15= 300 coins.
Manu said:
6 years ago
@All.
According to me, the solution is;
Rs.30 = 3000p (30X100=3000).
1:2:3 = 3000.
so to find out the number of 5 p coins:
3000X (3/6) = 500X3 = 1500.
Ans: 1500
Please tell me, where I am going wrong?
According to me, the solution is;
Rs.30 = 3000p (30X100=3000).
1:2:3 = 3000.
so to find out the number of 5 p coins:
3000X (3/6) = 500X3 = 1500.
Ans: 1500
Please tell me, where I am going wrong?
Swapnil said:
6 years ago
Agree @Manu.
Please, someone, clarify it clearly.
Please, someone, clarify it clearly.
GuruVardhan said:
6 years ago
Let 30rs = 300p.
So 1x+2x+3x = 300.
x = 50.
So 1x:2x:3x = 50:100:150.
Ans is 150.
So 1x+2x+3x = 300.
x = 50.
So 1x:2x:3x = 50:100:150.
Ans is 150.
(1)
MANU said:
6 years ago
Ratio in amount in paisa 25:20:15.
No.of 5 paisa coins = (15x3000)/(60x5).
= 150 coins.
No.of 5 paisa coins = (15x3000)/(60x5).
= 150 coins.
(1)
Sahana said:
5 years ago
Why they are equated to 30?
In problem, it is given that 30 rs in all, hence it would be equated to 90, right?
In problem, it is given that 30 rs in all, hence it would be equated to 90, right?
Sandhiya said:
5 years ago
First convert 30rs to paise , ie 3000p.
Now, 25p:10p:5p = 1:2:3.
And given that, their sum is 3000p.
So, 25x + 10(2x) + 5(3x) = 3000 paise
60x = 3000
x=50.
So the value of 5p is 5*3*50 = 750.
But they asked No. Of 5p coins so, -> 750/5 = 150.
Now, 25p:10p:5p = 1:2:3.
And given that, their sum is 3000p.
So, 25x + 10(2x) + 5(3x) = 3000 paise
60x = 3000
x=50.
So the value of 5p is 5*3*50 = 750.
But they asked No. Of 5p coins so, -> 750/5 = 150.
(3)
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