Aptitude - Ratio and Proportion - Discussion

Rs.1=100p.
Rs.30=3000p,
Total Paisas inside = 3000p,
Sum of ratios= 1+2+3=6.
For the third ratio i.e for 5p, the equation will be: 3/6*3000÷ 3= 50.

5 paisa coin ratio value is 3.

So the answer must be multiple of 3 first try to check its multiple.

25p. 10p. 5p.
1/4 : 2/10 : 3/20/

LCM=20, then the ratio is 5:4:3.
Sum of the ratio =12---------60
1---------5
Then 5 = 25,4 = 20,3 = 15.

Convert into coin then 5p coin = 100 * 15/20 = 300.
That's the right answer.

30 rupees = 3000p.
The sum of three ratios (1:2:3)=6.

1 ratio =3000/6= 500 paisa.
When the 1 ratio is equal to 500 paise then the 3 ratio is equal to 500×3 which is equal to 1500 paisa.
And to convert 1500 paisa into 5 paisa coins we divide 1500 by 5 which is equal to 300.
Hence, 300 is the right answer.

Let,
25p=1x,
10p=2x and 5p=3x.

Rs 30 = 30 * 100 = 3000p,
We know that;
1x + 2x + 3x = 3000,
x= 50.
Now.
5p= 3x.
5p= 3*50.
5p= 150.

To solve this problem, we first need to find the total value of each type of coin and then use the given information to determine the number of 5 p coins.

Let's denote:
-( x) as the number of 25 p coins,
-( 2x) as the number of 10 p coins (since it's twice the number of 25 p coins),
-( 3x) as the number of 5 p coins (since it's thrice the number of 25 p coins).

The total value of the coins can be expressed as:
[ 25x + 10(2x) + 5(3x) = 3000] (converted Rs. 30 into paise).

Solve for (x):

[ 25x + 20x + 15x = 3000]
[ 60x = 3000]
[ x = frac{3000}{60}]
[x = 50]
Now, we know that there are 50 coins of 25 paise each.
So, the number of 5 paise coins is ( 3x = 3 * 50 = 150).
Therefore, there are 150 - 5 paise coins in the bag.

1 : 2: 3
Let real value is;
k:2k:3k.

So,
K + 2k + 3k = 300(30rupees = 300paisa).
6k = 300
k = 50
3k = 3 * 50 = 150.