Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 8)
8.
In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Answer: Option
Explanation:
A : B = 100 : 80.
A : C = 100 : 72.
 |
B | = |  |
B | x | A |  |
= | |
80 | x | 100 | |
= | 10 | = | 100 | = 100 : 90. |
| C | A | C | 100 | 72 | 9 | 90 |
B can give C 10 points.
Discussion:
13 comments Page 1 of 2.
Kiran said:
8 years ago
@All.
In 100 point game b gets only 80 point and C gets 72 point.
Where B gets 80, C can get 72 point, here at this time B gets 80 points but in our question, we need to calculate for 100 points.
WIn 80 point game B beat C by 8 point.
Then in 100 point game B beat C by 10 point.
80---------8
100-------?
(100*8)÷80=10.
In 100 point game b gets only 80 point and C gets 72 point.
Where B gets 80, C can get 72 point, here at this time B gets 80 points but in our question, we need to calculate for 100 points.
WIn 80 point game B beat C by 8 point.
Then in 100 point game B beat C by 10 point.
80---------8
100-------?
(100*8)÷80=10.
Vinay said:
1 decade ago
From b:c we know 80-72 = 8.
i.e from 80 points b can give c 8 points.
In time and work problems we assume work is always one (1).
In the same way we have to calculate for 100 points in races topic because getting 100 points is the game winner.
For 80 b can give c 8 points.
For 100 b can give c 10 points.
i.e from 80 points b can give c 8 points.
In time and work problems we assume work is always one (1).
In the same way we have to calculate for 100 points in races topic because getting 100 points is the game winner.
For 80 b can give c 8 points.
For 100 b can give c 10 points.
Maka M said:
5 years ago
We can use it in other way.
A:B:C = 100:80:72.
Here the question calculate the B can give C. So;
B:C =80 :72 ------B/C=80/72.
B is 100 points then C = 72B/80 here B = 100
C= (72 * 100)/80 = 90.
So, B can give C is = 100 - 90 = 10.
A:B:C = 100:80:72.
Here the question calculate the B can give C. So;
B:C =80 :72 ------B/C=80/72.
B is 100 points then C = 72B/80 here B = 100
C= (72 * 100)/80 = 90.
So, B can give C is = 100 - 90 = 10.
(2)
Hanumantharao said:
1 decade ago
Sorry can't understand why you are writing (B/A*A/C) why don't write (A/B*A/C) or (B/A*C/A) is there any reason please tell me?
Stilllearning said:
1 decade ago
I have never seen a question like this before. How are you suppose to know how many points each person has at the beginning?
Ambica said:
1 decade ago
I didn't get the 2nd last step.
Can anyone explain that?
How 10/9 became 100/90 why?
Why we multiplied 10/9*10/10?
Can anyone explain that?
How 10/9 became 100/90 why?
Why we multiplied 10/9*10/10?
Leo. said:
8 years ago
@ALL.
I am not able to understand these kinds of problems. Please, could someone explain clearly?
Thanks.
I am not able to understand these kinds of problems. Please, could someone explain clearly?
Thanks.
Pankaj said:
1 decade ago
If we have to calculate for b/c then we should do b/a * a/c to cancel a.
Rajesh said:
1 decade ago
Couldn't understand the problem? What is being asked and what to solve?
Namrata said:
10 years ago
How 10/9 became 100/90?
Why 10/9 multiply by 10/10?
Why 10/9 multiply by 10/10?
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