Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 8)
8.
In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Answer: Option
Explanation:
A : B = 100 : 80.
A : C = 100 : 72.
![]() |
B | = | ![]() |
B | x | A | ![]() |
= | ![]() |
80 | x | 100 | ![]() |
= | 10 | = | 100 | = 100 : 90. |
C | A | C | 100 | 72 | 9 | 90 |
B can give C 10 points.
Discussion:
13 comments Page 2 of 2.
Kapil said:
1 decade ago
How is ration of B 80 and that of C is 72?
Makau said:
1 decade ago
Am getting 80/72 why is it 100/90?
Pavithra said:
5 years ago
Why multiple 10/9 with 10?
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