Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 13)
13.
In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Answer: Option
Explanation:
A : B = 100 : 75
B : C = 100 : 96.
 A : C = |
 |
A | x | B |  |
= | |
100 | x | 100 | |
= | 100 | = 100 : 72. |
| B | C | 75 | 96 | 72 |
A beats C by (100 - 72) m = 28 m.
Discussion:
11 comments Page 1 of 2.
Vishal ahire NIPER said:
1 year ago
A:B:C an important ratio,
when, A = 100 then at that time B = 75
when B = 100 then at that time C = 96
so, according to ratio A:B: C = 100:75:X
Let, calculate according to that when,
when B = 100 then C=96 so if B = 75 then C = ?
by cross-calculation we can determine, if
B is 100 = C is 96,
B is 75 = C is X.
X= (75 x 96)/100,
X= 72,
so, if A:B:C = 100:75:72.
The difference between the distance the A and C is (100-72 = 28).
when, A = 100 then at that time B = 75
when B = 100 then at that time C = 96
so, according to ratio A:B: C = 100:75:X
Let, calculate according to that when,
when B = 100 then C=96 so if B = 75 then C = ?
by cross-calculation we can determine, if
B is 100 = C is 96,
B is 75 = C is X.
X= (75 x 96)/100,
X= 72,
so, if A:B:C = 100:75:72.
The difference between the distance the A and C is (100-72 = 28).
Priya said:
5 years ago
When A covers 100m.
B covers 100-25=75m.
When B covers 100m.
C covers 96m.
Hence, when A cover 100m.
C cover (4+25)=29-1(we are considering it twice), hence the answer is 28m.
B covers 100-25=75m.
When B covers 100m.
C covers 96m.
Hence, when A cover 100m.
C cover (4+25)=29-1(we are considering it twice), hence the answer is 28m.
(2)
Prince Raj Kumar said:
6 years ago
Please give me or short tricks in this number. Thanks.
Leo said:
7 years ago
Thanks for the informations.
Khandaker Sajib Ahmed said:
7 years ago
It means, When A covers 100m, B covers=100-25=75m. And again, When B covers=100m, C covers=100-4=96m.
ATQ, When B covers 100m, C covers 96m.
when B covers 75m, C covers 96*75/100=72m.
So A can beat C by=100-72=28m.
ATQ, When B covers 100m, C covers 96m.
when B covers 75m, C covers 96*75/100=72m.
So A can beat C by=100-72=28m.
(1)
Vivek said:
7 years ago
How did you get 72? @Praveen.
(1)
Kajal said:
8 years ago
Guys, just read the question, the comma after 100 m indicates 100 m is applicable for the statement before 'and' and after 'and'.
Praveen said:
9 years ago
When A Travels 100 m, B travels 75 m => A:B = 100:75.
When B Travels 100 m, C travels 96 m.
When B Travels 75 m, C travels (96 x 75)/100 = 72 m => B:C = 75:72.
Therefore, A:B:C = 100:75:72.
So, when A Travels 100 m, C travels 72 m.
Therefore, A beat C by 28 m.
When B Travels 100 m, C travels 96 m.
When B Travels 75 m, C travels (96 x 75)/100 = 72 m => B:C = 75:72.
Therefore, A:B:C = 100:75:72.
So, when A Travels 100 m, C travels 72 m.
Therefore, A beat C by 28 m.
(3)
Khushboo said:
10 years ago
Here it is B can beat C by 4m which means C is far from B by 4m, so it has traveled 21m
(1)
Yuvaraj said:
1 decade ago
@Syed,
Here it states that "In a 100 m race, A can beat B by 25 m and B can beat C by 4 m." It mesns that B beat C by 4 m in 100m race. So B beat C by 3 m in 75m race.
Hence A beats C in 100 m race by 28m (25+3).
Here it states that "In a 100 m race, A can beat B by 25 m and B can beat C by 4 m." It mesns that B beat C by 4 m in 100m race. So B beat C by 3 m in 75m race.
Hence A beats C in 100 m race by 28m (25+3).
(1)
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