Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 13)
13.
In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Answer: Option
Explanation:
A : B = 100 : 75
B : C = 100 : 96.
A : C = | A | x | B | = | 100 | x | 100 | = | 100 | = 100 : 72. | ||||
B | C | 75 | 96 | 72 |
A beats C by (100 - 72) m = 28 m.
Discussion:
11 comments Page 1 of 2.
Syed Tajudeen.S said:
1 decade ago
When A runs 100m then B runs 75m and C runs 71m and A beats C by 28m. Then how come 29m? please do clear my doubts
(1)
Yuvaraj said:
1 decade ago
@Syed,
Here it states that "In a 100 m race, A can beat B by 25 m and B can beat C by 4 m." It mesns that B beat C by 4 m in 100m race. So B beat C by 3 m in 75m race.
Hence A beats C in 100 m race by 28m (25+3).
Here it states that "In a 100 m race, A can beat B by 25 m and B can beat C by 4 m." It mesns that B beat C by 4 m in 100m race. So B beat C by 3 m in 75m race.
Hence A beats C in 100 m race by 28m (25+3).
(1)
Khushboo said:
10 years ago
Here it is B can beat C by 4m which means C is far from B by 4m, so it has traveled 21m
(1)
Praveen said:
9 years ago
When A Travels 100 m, B travels 75 m => A:B = 100:75.
When B Travels 100 m, C travels 96 m.
When B Travels 75 m, C travels (96 x 75)/100 = 72 m => B:C = 75:72.
Therefore, A:B:C = 100:75:72.
So, when A Travels 100 m, C travels 72 m.
Therefore, A beat C by 28 m.
When B Travels 100 m, C travels 96 m.
When B Travels 75 m, C travels (96 x 75)/100 = 72 m => B:C = 75:72.
Therefore, A:B:C = 100:75:72.
So, when A Travels 100 m, C travels 72 m.
Therefore, A beat C by 28 m.
(3)
Kajal said:
8 years ago
Guys, just read the question, the comma after 100 m indicates 100 m is applicable for the statement before 'and' and after 'and'.
Vivek said:
7 years ago
How did you get 72? @Praveen.
(1)
Khandaker Sajib Ahmed said:
7 years ago
It means, When A covers 100m, B covers=100-25=75m. And again, When B covers=100m, C covers=100-4=96m.
ATQ, When B covers 100m, C covers 96m.
when B covers 75m, C covers 96*75/100=72m.
So A can beat C by=100-72=28m.
ATQ, When B covers 100m, C covers 96m.
when B covers 75m, C covers 96*75/100=72m.
So A can beat C by=100-72=28m.
(1)
Leo said:
7 years ago
Thanks for the informations.
Prince Raj Kumar said:
6 years ago
Please give me or short tricks in this number. Thanks.
Priya said:
5 years ago
When A covers 100m.
B covers 100-25=75m.
When B covers 100m.
C covers 96m.
Hence, when A cover 100m.
C cover (4+25)=29-1(we are considering it twice), hence the answer is 28m.
B covers 100-25=75m.
When B covers 100m.
C covers 96m.
Hence, when A cover 100m.
C cover (4+25)=29-1(we are considering it twice), hence the answer is 28m.
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers