Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 13)
13.
In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
Answer: Option
Explanation:
A : B = 100 : 75
B : C = 100 : 96.
 A : C = |
 |
A | x | B |  |
= | |
100 | x | 100 | |
= | 100 | = 100 : 72. |
| B | C | 75 | 96 | 72 |
A beats C by (100 - 72) m = 28 m.
Discussion:
11 comments Page 2 of 2.
Syed Tajudeen.S said:
1 decade ago
When A runs 100m then B runs 75m and C runs 71m and A beats C by 28m. Then how come 29m? please do clear my doubts
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers