Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 11)
11.
On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Answer: Option
Explanation:
(C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)
C.P. of 12 balls = S.P. of 17 balls = Rs.720.
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720 | ![]() |
= Rs. 60. |
12 |
Discussion:
91 comments Page 3 of 10.
Shravani said:
1 decade ago
How could you take cp-sp=cp?
Sushmita said:
1 decade ago
We can also solve it as:
Let the CP of 1 ball be x. then,
CP of 17 balls will be 17x.
Given that: loss=CP of 5 balls i.e. 5x.
Therefore, CP-SP=loss =>17x-720=5x=>x=Rs 60.
Let the CP of 1 ball be x. then,
CP of 17 balls will be 17x.
Given that: loss=CP of 5 balls i.e. 5x.
Therefore, CP-SP=loss =>17x-720=5x=>x=Rs 60.
(1)
Krunal said:
1 decade ago
SP = CP*(loss)or(gain)%.
SP = 720;
CP = x;
loss = 5 of CP = 5 (x);
720 = x*5x;
5x*x = 720;
x^2 = 144;
x = 12;
720/12 = 60.
SP = 720;
CP = x;
loss = 5 of CP = 5 (x);
720 = x*5x;
5x*x = 720;
x^2 = 144;
x = 12;
720/12 = 60.
Atul1487 said:
1 decade ago
@Murali.
You are incorrect.
As acc to you.
Given in the problem.
5x/17 = x-720/17.
But actual is.
5x/17 = x/17-720/17.
Now you will get incorrect answer.
You are incorrect.
As acc to you.
Given in the problem.
5x/17 = x-720/17.
But actual is.
5x/17 = x/17-720/17.
Now you will get incorrect answer.
Yaghu said:
1 decade ago
Let C.P for 1 ball = x;
S.P for 1 ball is = 720/17;
Loss = C.P of 5 balls = 5x (5x is overall loss).
For loss in 1 ball = 5x/17 .
Therefore,
C.P - S.P = loss(for 1 ball).
x-720/17 = 5x/17.
x = 60.
S.P for 1 ball is = 720/17;
Loss = C.P of 5 balls = 5x (5x is overall loss).
For loss in 1 ball = 5x/17 .
Therefore,
C.P - S.P = loss(for 1 ball).
x-720/17 = 5x/17.
x = 60.
Sush said:
1 decade ago
Cost of 1 ball = x.
Cost of 17 ball = 17x.
Selling price of 17 ball = 720.
Loss = 5x where x is price of 1 ball.
Loss = cp - sp.
5x = 17x - 720.
x = 60.
Cost of 17 ball = 17x.
Selling price of 17 ball = 720.
Loss = 5x where x is price of 1 ball.
Loss = cp - sp.
5x = 17x - 720.
x = 60.
Tina said:
1 decade ago
In the question, it is given the that on selling 17 balls at rs 720, the loss is equal to cost prize of 5 balls, but why have we subtracted it from cost prize of 17 balls when it is no where mentioned in the question ?
Ramesh Yadav said:
1 decade ago
@Tina.
Observing this question you find that he say.
Selling of 17 balls Rs. 720 is equal to the loss of cost prize of 5 balls. Then we find that.
Let us suppose C.P. is x.
Then C.P. of 17 balls - S.P. of 17 balls = C.P. of 5 ball.
17x-720 = 5x.
Then 12x = 720.
x = 720/12.
x = 60.
Observing this question you find that he say.
Selling of 17 balls Rs. 720 is equal to the loss of cost prize of 5 balls. Then we find that.
Let us suppose C.P. is x.
Then C.P. of 17 balls - S.P. of 17 balls = C.P. of 5 ball.
17x-720 = 5x.
Then 12x = 720.
x = 720/12.
x = 60.
Reja said:
1 decade ago
Any one may explain in a simple form?
Baskar said:
1 decade ago
Loss = C.P-S.P.
From given: S.P of 17 balls = 720 R.S.
Loss = C.P of 5 balls.
From 1st equation.
C.P of 5 balls = C.P of 17 balls - S.P of 17 balls.
Let C.P of 1 ball = x.
5x = 17x-720.
12x = 720.
x = 60.
From given: S.P of 17 balls = 720 R.S.
Loss = C.P of 5 balls.
From 1st equation.
C.P of 5 balls = C.P of 17 balls - S.P of 17 balls.
Let C.P of 1 ball = x.
5x = 17x-720.
12x = 720.
x = 60.
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