Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 11)
11.
On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:
Rs. 45
Rs. 50
Rs. 55
Rs. 60
Answer: Option
Explanation:

(C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)

C.P. of 12 balls = S.P. of 17 balls = Rs.720.

C.P. of 1 ball = Rs. 720 = Rs. 60.
12

Discussion:
91 comments Page 4 of 10.

Sunny said:   1 decade ago
How C.P. of 12 balls?

Ankit Ardeshana said:   10 years ago
Loss for 17 balls = cp of 5 balls.

=> cp of 17 balls - sp of 17 balls = cp of 5 balls.

=> (cp of 17 balls - cp of 5 balls) = sp of 17 balls.

But sp of 17 balls = 720.

=>cp of 12 balls = 720.

=>cp of 1 ball = 720/12 = 60.

Sikandar said:   10 years ago
17 C.P-17 S.P = 5 C.P.

12 C.P = 17 C.P > 17 C.P = 720.

12 C.P = 720.

C.P = 60.

Avijit said:   10 years ago
Let C.P is x then.

According to question condition of loss.

(C.P of 17 balls) - (S.P of 17 balls) = (C.P of 5 balls).

=> (17*x) - 720 = (5*x).

=> 17x - 5x =720.

=> 12x = 720.

x = 720/12.

=> x = 60.

Mahnoor said:   10 years ago
@Sunny.

We will subtract the balls 17-5 = 12.

Hope you got it.

Tarun said:   10 years ago
More easy: 17-5 = 12.

And 720/12 = 60.

Uma said:   9 years ago
C.P of 17 balls = x.

Loss = C.P of 5 balls.
1 ball C.P is x/17.
5 balls C.P is 5x/17.
Loss = 5x/17.

17 balls C.P = 17 balls S.P+Loss.

x = 720+5x/17.
12x = 720*17.
x = 60*17.

Then each ball price is (x/17) = ((60*17)/17) = 60.

Ram Prakash said:   9 years ago
Can anyone tell me the short tricks to find the answer to this question?

Rita said:   9 years ago
Here we found Loss.

So Equation is Loss = CP - SP (but in case of profit -> Profit = SP - CP).

Loss (CP of 5 balls) = CP (CP of 17 balls) - SP (SP of 17 balls).
(Cost of 1 Ball) * 5 = 17 - 720.
(Cost of 1 Ball) * 5 - 17 = - 720.
(Cost of 1 Ball) - 12=- 720 =720/12 =60.

So, Cost of 1 ball is Rs. 60.

Pawar Upendra Dinesh said:   9 years ago
Nice explanations, clear to understand.


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