Aptitude - Profit and Loss - Discussion

@Vinothini

Listen, no need to worry abt x an all..

We have one formulae:

Gain*100/c.p=loss*100/c.p

We obtain:
gain=loss

s.p-c.p=c.p-s.p
1920-c.p=c.p-1280=>3600=2c.p

c.p=1600;
For profit 20%,already profit 3200-1600=1600is there.
1600*20/100 = 400; profit=s.p-c.p= > s.p=1600+400 = 2000

If profit on condition 1 and loss on codition 2 is same

then, cost prise=1280+1920/2
=1600
after that on 25% profit=1600*125/100
=2000
that prove that c is the ans.

Friends you don't know what is cost price first we can find cost price and thus (1950+1280)/2 we get 1600.

So,
Cost price 100 = 1600.

125 = 2000.

Thank you kavi.

Thanks aamir your explaination is awesome.

Thank you kavi.

Hai guys simple method..........

Given sum is 2 selling price
-->first one is profit(sp1)
-->second one is loss(sp2)
so......
given profit & loss value
but.......
have no given the original price(x)
sp1-x=sp2+x
1920-x=1280+x
x=320
original price=sp1-x
so op=1600
then 25% profit
porofit=1600*1.25
=2000

That's all.

We have to calculate s.p
so formula is,
s.p=(100+profit%)*c.p/100.............(1)
now look at formula
we have profit % only we have to calculate c.p
now read our problem
assume,
profit=loss=x
sp1=1920
sp2=1280

sp1-x=sp2+x
1920-x=1280+x
1920-1280=2x
640=2x
x=320
Now we have formula to calculate c.p
c.p=s.p-profit...........................(2)
c.p=1920-320
c.p=1600
now put values in formula(1)
we get,
s.p=(100+25)*1600/100
s.p=125*1600/100
s.p=2000

Therefore selling price is 2000 to earn 25% profit

Its Simple, we have to use Gain% formula, see

Gain% = Gain*100/CP or SP-CP *100/CP
Let CP = x, then

case I = 1920 - x *100/x
case II = x - 1280*100/x [here i use loss% formula]
Now, compare the two cases, we get
1920 - x*100/x = x -1280*100/x
or 1920x - x^2 = x^2 - 1280
or 1920x - x^2 - x^2 + 1280 = 0
or 3200x - 2x^2 = 0
or 3200 = 2x
x = 1600 = CP
Now, use SP formula
S.P = 1 + Gain% * CP
1 + 25/100 * 1600
125/100 *1600
= 2000

1920+1280/2=1600
25%of 1600=400
1600+400=2000