Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
Relative speed = | = (45 + 30) km/hr | |||||||
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We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
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500 x | 6 | ![]() |
= 24 sec. |
125 |
Discussion:
81 comments Page 7 of 9.
Sujee said:
4 years ago
Why do we take 500 instead of 1000?
Please anyone explain me.
Please anyone explain me.
(1)
Jay said:
6 years ago
500 should be the initial distance between two trains.
Raju said:
8 years ago
How 125÷6 came in this problem? Please explain.
Kineg said:
7 years ago
Can anyone explain to me how the distance came 500?
Ruturaj said:
6 years ago
Not getting this, Please anyone explain it clearly.
Manish said:
9 years ago
I am not getting understand where we got 5/18.
Nana said:
1 decade ago
Why was the speeds added instead subtracting?
Baseer said:
1 decade ago
5/18 came from? Can some one tell me please.
Ankit gohel said:
6 years ago
If speed equals then what? Please tell me.
Reho Rex said:
6 years ago
This is the trick part of question no.14.
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