Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
Relative speed = | = (45 + 30) km/hr | |||||||
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We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
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500 x | 6 | ![]() |
= 24 sec. |
125 |
Discussion:
81 comments Page 6 of 9.
Aarush said:
1 decade ago
This is wrong. Try formula number 8 in formula section. We shoud use distance 1000.
Krishna said:
1 year ago
@Sahil
Speed = d/t
Speed = 125/6
t = d/speed.
t = 500/(125/6) = 500 * 6/125.
Speed = d/t
Speed = 125/6
t = d/speed.
t = 500/(125/6) = 500 * 6/125.
Sidhant said:
1 decade ago
What If we had to find the time taken by fastest train instead of slowest train?
Shekhar said:
1 decade ago
Instead of DRIVER if whole length of faster train then how to calculate?
Mubarak said:
7 years ago
@Kineg.
Distance covered = length of the slower train.
So, it is 500m.
Distance covered = length of the slower train.
So, it is 500m.
Nitheesh said:
8 years ago
What if they had asked time for a faster train?
Can anyone solve this?
Can anyone solve this?
Swati said:
1 decade ago
Nice one. We have to calculate for drive i.e. for man, not for train.
Ashu baba said:
10 years ago
Conclusion is faster or slower answer will be same (examiner troll).
Vibhor said:
1 decade ago
Ans is correct. I did mistake at first time also.
It is a good one.
It is a good one.
Kush said:
4 years ago
What length we should consider if it is asked for faster train?
(1)
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