Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
12 sec
24 sec
48 sec
60 sec
Answer: Option
Explanation:

Relative speed = = (45 + 30) km/hr
= ( 75 x 5 ( m/sec
18
= ( 125 ( m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Therefore Required time = ( 500 x 6 ( = 24 sec.
125

Discussion:
81 comments Page 6 of 9.

Aarush said:   1 decade ago
This is wrong. Try formula number 8 in formula section. We shoud use distance 1000.

Krishna said:   1 year ago
@Sahil
Speed = d/t
Speed = 125/6
t = d/speed.
t = 500/(125/6) = 500 * 6/125.

Sidhant said:   1 decade ago
What If we had to find the time taken by fastest train instead of slowest train?

Shekhar said:   1 decade ago
Instead of DRIVER if whole length of faster train then how to calculate?

Mubarak said:   7 years ago
@Kineg.

Distance covered = length of the slower train.

So, it is 500m.

Nitheesh said:   8 years ago
What if they had asked time for a faster train?

Can anyone solve this?

Swati said:   1 decade ago
Nice one. We have to calculate for drive i.e. for man, not for train.

Ashu baba said:   10 years ago
Conclusion is faster or slower answer will be same (examiner troll).

Vibhor said:   1 decade ago
Ans is correct. I did mistake at first time also.

It is a good one.

Kush said:   4 years ago
What length we should consider if it is asked for faster train?
(1)


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