Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
12 sec
24 sec
48 sec
60 sec
Answer: Option
Explanation:

Relative speed = = (45 + 30) km/hr
= ( 75 x 5 ( m/sec
18
= ( 125 ( m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Therefore Required time = ( 500 x 6 ( = 24 sec.
125

Discussion:
81 comments Page 7 of 9.

Rajesh said:   1 decade ago
Well done chandana at first I made same mistake by taking distance 1000m instead of 500.

I have got 15. Anyway, not bad.

Swati said:   1 decade ago
Nice one. We have to calculate for drive i.e. for man, not for train.

Chandana said:   1 decade ago
Driver is starting of the train. If slower train pass the driver of the faster train automatically it pass the total train. Is it right?

Keerthi srihari said:   9 years ago
Here there is asking only time taken by slower train to cross a faster train here assume the driver of the faster train is considered as a static object so we take only slower train distance.

Manish said:   9 years ago
I am not getting understand where we got 5/18.

Xavi said:   9 years ago
Yes, 24sec is the correct answer.

Because the math required us to find out only the passing time of the driver of the slower train.

Ankit said:   10 years ago
The question here is find the time when driver meet not find the time when the train crosses each other.

Alice said:   10 years ago
This s a good tricky question. I too made a mistake for the first time. But now I got it. Thank you for the explanation.

Ashu baba said:   10 years ago
Conclusion is faster or slower answer will be same (examiner troll).

AMAR said:   10 years ago
In that condition, take total length both train.

i.e 1000/t = (75*5/18).

We get the answer = 48 s.


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