Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 7 of 24.
Sundar said:
2 decades ago
Hi Afshu,
Since both trains are in same length, we are taking it as 2X (X + X) in order to calculate the distance.
Otherwise, if the length of the trains are different then we will take it as X1 + X2 for calculating the length.
Have a nice day!
Since both trains are in same length, we are taking it as 2X (X + X) in order to calculate the distance.
Otherwise, if the length of the trains are different then we will take it as X1 + X2 for calculating the length.
Have a nice day!
Jitendra chaudhary said:
1 decade ago
Let the length of each train is X.
Than total length which should be covered to pass the train = 2X.
The speed of train to pass the 2X distance = 2X/36.
The relative distance of trains = 46-36 = 10 km /hr.
So 10*(5/18) = 2X/36.
X = 50 answer.
Than total length which should be covered to pass the train = 2X.
The speed of train to pass the 2X distance = 2X/36.
The relative distance of trains = 46-36 = 10 km /hr.
So 10*(5/18) = 2X/36.
X = 50 answer.
Priya biradar said:
8 years ago
The Speed of 1st train = 46km/hr,
Convert it into m/s===== 46*5/18=115\9,
length= speed*time
=115/9*36=460m
Speed of 2nd train = 36km/hr --> convert it into ms=====36*5/18=10
length= speed*time
= 10*36=360m
= 460-360=100
For 2 train 100/2=50m.
Convert it into m/s===== 46*5/18=115\9,
length= speed*time
=115/9*36=460m
Speed of 2nd train = 36km/hr --> convert it into ms=====36*5/18=10
length= speed*time
= 10*36=360m
= 460-360=100
For 2 train 100/2=50m.
Khushnood Ali said:
3 years ago
Speed = distance/time.
Speed = 2x/36 (2x assumed as distance covered by train and 36secs time is given).
The relative speed = 25/9 (calcuated in solution)
From both equation relative speed and speed should be same that's why;
2x/36 = 25/9.
Speed = 2x/36 (2x assumed as distance covered by train and 36secs time is given).
The relative speed = 25/9 (calcuated in solution)
From both equation relative speed and speed should be same that's why;
2x/36 = 25/9.
(3)
Yoo said:
6 months ago
The Length of the train be x.
(u-v) = 46 - 36 = 10km/hr = 25/9,
T = (a+b)/(u-v).
T is the time difference of 36 sec.
(u-v)relative speed train moves in the same direction.
By Substitute all values;
36 = (x+x)/(25/9),
36 * 25/9 = 2x,
x = 50.
(u-v) = 46 - 36 = 10km/hr = 25/9,
T = (a+b)/(u-v).
T is the time difference of 36 sec.
(u-v)relative speed train moves in the same direction.
By Substitute all values;
36 = (x+x)/(25/9),
36 * 25/9 = 2x,
x = 50.
(4)
C.A.Reddy said:
1 decade ago
Since we are talking about relative speed (means b/w two trains. ).
Hence taking distance also combing length of two trains.
At final we are making two train details as single train details after finding we can extract two trains details.
Hence taking distance also combing length of two trains.
At final we are making two train details as single train details after finding we can extract two trains details.
Raghav said:
1 decade ago
In question given that both trains are running in same direction.
So in generalize form we assume that both the trains are started from same point.
So distance covered should be equal to x.
And x=100. I think 100 is the right answer.
So in generalize form we assume that both the trains are started from same point.
So distance covered should be equal to x.
And x=100. I think 100 is the right answer.
Mohammad yasir said:
8 years ago
If the first train crosses slower train by relative speed 10kmph. It means the whole length of this train crosses slower train in 36 seconds.
Which literally means the same train crosses the slower train twice when we treat it a point.
Which literally means the same train crosses the slower train twice when we treat it a point.
SHUBHaM SaKHaRE said:
8 years ago
Let the length of both trains be 'x'.
Distance covered by slower train = 36*(36*5/18),
Hence total distance covered by faster train= 2x+36*(36*5/18),
Hence we get;
46*5/18=(2x+36*(36*5/18))/36,
By solving this on calc we get;
X=50.
Distance covered by slower train = 36*(36*5/18),
Hence total distance covered by faster train= 2x+36*(36*5/18),
Hence we get;
46*5/18=(2x+36*(36*5/18))/36,
By solving this on calc we get;
X=50.
Jayanth said:
2 decades ago
In problem, the two trains r running on parellel lines in the same direction, how can we take both of it as same length as x . can it be two trains of different lengths running parallel. Is this is assumption or fact.
Explain me
Explain me
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