Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
234 comments Page 7 of 24.
P sudhakar said:
2 decades ago
Why did take the differences of speed?
Tintu said:
2 decades ago
Cant we do like:
relatv speed=10km/hr
Time=36 sec=.6hr
Then 2x distance is given by 10*.6 hours=6hrs
So x=3hrs
relatv speed=10km/hr
Time=36 sec=.6hr
Then 2x distance is given by 10*.6 hours=6hrs
So x=3hrs
Anne87 said:
2 decades ago
Good day! I just want to know why you used 2X/36? why did you used 36? Thank you!
Taj said:
2 decades ago
Please clarify my doubts.
How it is possible ? 50 m.
How it is possible ? 50 m.
Srikanth said:
2 decades ago
@Taj.
You just go through the Train formulas you will get clear idea.
You just go through the Train formulas you will get clear idea.
Rammurthy said:
2 decades ago
How this equation: 2x/36 = 25/9?
Pavithra said:
2 decades ago
Why not we take 2x/46 ?
Sid said:
2 decades ago
What is relative speed. Please explain me in somewhat detail manner. Cant understand.
Venkatesh said:
2 decades ago
Thanks jelli.
Venkatesh said:
2 decades ago
Hi jelli, can you give a important equations used in that kind of problems.
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