Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 4 of 24.
Taj said:
1 decade ago
Please clarify my doubts.
How it is possible ? 50 m.
How it is possible ? 50 m.
Srikanth said:
1 decade ago
@Taj.
You just go through the Train formulas you will get clear idea.
You just go through the Train formulas you will get clear idea.
Rammurthy said:
1 decade ago
How this equation: 2x/36 = 25/9?
Pavithra said:
1 decade ago
Why not we take 2x/46 ?
Sid said:
1 decade ago
What is relative speed. Please explain me in somewhat detail manner. Cant understand.
Venkatesh said:
1 decade ago
Thanks jelli.
Venkatesh said:
1 decade ago
Hi jelli, can you give a important equations used in that kind of problems.
Ster said:
1 decade ago
2x as distance only makes sense if the faster train start behind the slower train. If they were right next to each other at the start, the distance traveled would only be x. Question does not clarify this. Please amend.
Vinayak said:
1 decade ago
Can we calculate this example by (a+b) / (u-v)?
Hasi said:
1 decade ago
Distance traveled by train =x
2 trains have same length
there are two trains traveled at the same time
means total distance traveled by the train =2x
Relative distance of the train is =(46-36)=10km/hr
but options are given in sec so,we have to convert into m/sec
10*(5/18)=25/9
total distance=speed*time
2x=(25/9)*36
2x=100
x=50
2 trains have same length
there are two trains traveled at the same time
means total distance traveled by the train =2x
Relative distance of the train is =(46-36)=10km/hr
but options are given in sec so,we have to convert into m/sec
10*(5/18)=25/9
total distance=speed*time
2x=(25/9)*36
2x=100
x=50
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