Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
50 m
72 m
80 m
82 m
Answer: Option
Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 10 x 5 m/sec
18

   = 25 m/sec
9

2x = 25
36 9

2x = 100

x = 50.

Discussion:
232 comments Page 3 of 24.

Samreen Sultana said:   2 years ago
= [10*5/18]*36.
= 100.
= √100 = 50.
= 50 is the answer.
(9)

Roshan Kunwor said:   3 years ago
Because, when the faster train just crosses the slower, they should cover 2x distance since the length of the train is same.
(4)

Abhishek said:   3 years ago
Why you have done, 2x/36 = 25/9?
And why not 2x/46 = 25/9?

Please explain me clearly.
(8)

Shri.. said:   3 years ago
@Bushra Ahmed.

2x=25/9*36 = 900/9 = 100.
(2)

Yuva kumar said:   3 years ago
How 2x/36 = 25/9? Please explain me.
(1)

Judah said:   4 years ago
The train should be 100mtr. The solution converts both speeds of the 2 trains to m/s and multiply each m/s by 36 and get the difference of the speed at 36 sec, and that the answer.

Hope it will helps.
(3)

Basavaraj said:   4 years ago
Answer is 100mtr.

As per the relative speed concept and as per the given question both trains of equal length are at the same point so a faster train has crossed its own length or the length of another one to cross it completely.

So it has to travel x mtr to cross another one with a speed of 10km/hour more.
(6)

Shaik Chereesh said:   4 years ago
Relative displacement is x not 2x.
The relative speed is 10.
Time is independent of the frame of reference.
The above points are correct according to my basic knowledge of physics.

Please correct me if the wrong.

Bhavithra said:   4 years ago
What is the meaning of relative speed?

Shantanu singh parihar said:   5 years ago
We have 2x cause,
When the faster train passes to slower,
It is covering;
X+X distance(slower train +higher speed train),
So the total distance covered is 2X.
(1)


Post your comments here:

Your comments will be displayed after verification.