Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
50 m
72 m
80 m
82 m
Answer: Option
Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 10 x 5 m/sec
18

   = 25 m/sec
9

2x = 25
36 9

2x = 100

x = 50.

Discussion:
235 comments Page 3 of 24.

Khushnood Ali said:   3 years ago
Speed = distance/time.
Speed = 2x/36 (2x assumed as distance covered by train and 36secs time is given).

The relative speed = 25/9 (calcuated in solution)

From both equation relative speed and speed should be same that's why;
2x/36 = 25/9.
(3)

Joy khwaka said:   3 years ago
I know most of us are not understanding how 2x/36 comes,

Here is my explanation;

Here 2x is the distance, then 36 is time in seconds.
(5)

Chandini said:   3 years ago
Why we take 2x/36=25/9?

Can anyone please explain?
(9)

Samreen Sultana said:   3 years ago
= [10*5/18]*36.
= 100.
= √100 = 50.
= 50 is the answer.
(9)

Roshan Kunwor said:   4 years ago
Because, when the faster train just crosses the slower, they should cover 2x distance since the length of the train is same.
(4)

Abhishek said:   4 years ago
Why you have done, 2x/36 = 25/9?
And why not 2x/46 = 25/9?

Please explain me clearly.
(8)

Shri.. said:   4 years ago
@Bushra Ahmed.

2x=25/9*36 = 900/9 = 100.
(2)

Yuva kumar said:   4 years ago
How 2x/36 = 25/9? Please explain me.
(1)

Judah said:   5 years ago
The train should be 100mtr. The solution converts both speeds of the 2 trains to m/s and multiply each m/s by 36 and get the difference of the speed at 36 sec, and that the answer.

Hope it will helps.
(3)

Basavaraj said:   5 years ago
Answer is 100mtr.

As per the relative speed concept and as per the given question both trains of equal length are at the same point so a faster train has crossed its own length or the length of another one to cross it completely.

So it has to travel x mtr to cross another one with a speed of 10km/hour more.
(6)


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