Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
50 m
72 m
80 m
82 m
Answer: Option
Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 10 x 5 m/sec
18

   = 25 m/sec
9

2x = 25
36 9

2x = 100

x = 50.

Discussion:
232 comments Page 22 of 24.

Debojit said:   7 years ago
But they are in the same direction, How you add x+ x and not subtract?

Because it's given the same direction if it's opposite direction then it's not a problem. Please explain me.

Hemant manglani said:   6 years ago
Same Direction (46-36) = 10,
length= speed * time.
(10*5/18)*36 = 50.

Nelson said:   6 years ago
Why have you subtracted the speeds to get the relative speeds instead of adding them? Please explain.

Dhruvi said:   6 years ago
Is the faster train behind the slower one? Is that why we are adding length of both?

Siree said:   6 years ago
s1-s2=(L1+L2)/time.
46-36=2(L1+L2)/36,
10 * 5/18=2(L1+L2)/36,
50=2(L1+L2)/2,
50*2=2(L+1L2).
L1+L2=100/2 = 50.

Sunny said:   6 years ago
How, 2x=100 comes?

Subba said:   6 years ago
@Sunny.

We know that speed = distance /time, here apply the same, but here since two trains are moving in the same direction relative speed comes and it is 10km/hr.

Then distance = 10 * 5/18 * 36 = 100metres.
Therefore, 2x = 100 and hence x = 50m each.

PAVAN said:   6 years ago
How do we get 2x/36 = 25/9?

Rutvik said:   6 years ago
Please explain 25/9=2.7m/s.

If we use the formula a+b/u-v and if the length is equal then 2a/2.7 = 36.
Which comes to 2a = 36 * 2.7.

i.e.a=36*2.7/2 which comes to 48.6.

Then how it will be 50?

Ruchi chaubey said:   6 years ago
How did you take 2x?

Please explain.


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