Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = | ![]() |
10 x | 5 | m/sec |
| 18 |
| = | ![]() |
25 | m/sec |
| 9 |
|
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
234 comments Page 12 of 24.
Paddy said:
1 decade ago
If both are of same length but time taken by A to cross B is given i.e 36 minutes, it does not mean that the B train is at Rest.
B is also moving so total distance cover by A = length of A + length of B + some distance after starting.
Total dist travel by B = 360 m
Total dist travel by A = 460 m
Therefore diff is 100 m
i.e. Length of train A or B
B is also moving so total distance cover by A = length of A + length of B + some distance after starting.
Total dist travel by B = 360 m
Total dist travel by A = 460 m
Therefore diff is 100 m
i.e. Length of train A or B
Akshay said:
1 decade ago
Use formula
L=length S=Speed
(L1+L2)/(S1-S2)=Time taken by fast train to cross slow train
Let length of train be x
Relative speed = (46-36) * 5/18 m/s =50/18
(x+x)/(50/18) = 36
2x/50=2
2x=100
x=50.
L=length S=Speed
(L1+L2)/(S1-S2)=Time taken by fast train to cross slow train
Let length of train be x
Relative speed = (46-36) * 5/18 m/s =50/18
(x+x)/(50/18) = 36
2x/50=2
2x=100
x=50.
Shoeb said:
1 decade ago
In the question it's clearly mentioned two trains are of same length.
So we can use formula , two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
* So 46-36=10km/hr.
* 10 *5/18 : 25/9
* 25/9*36 :.100 ( both train )
* 100/2=50 each train.
Thanks.
So we can use formula , two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
* So 46-36=10km/hr.
* 10 *5/18 : 25/9
* 25/9*36 :.100 ( both train )
* 100/2=50 each train.
Thanks.
Sita said:
1 decade ago
What is relative speed?
Deepu said:
1 decade ago
Should be mentioned that the faster train started behind the slower train.
Manish barthwal said:
1 decade ago
It should be mentioned that the faster train started behind the slower train.
If both trains are started at same place then we do not get 2x, because faster train only cover x area which is his own length.
If both trains are started at same place then we do not get 2x, because faster train only cover x area which is his own length.
Sunil said:
1 decade ago
If a train has the length x and the other train of same length cross the train of length than distance travel by it must be x so my query is why we are taking length 2x instead of x. Please tell.
Chandan said:
1 decade ago
Length of the trains be x & 2x because after 36 second the faster train is going to pass the slower train. At that time faster train covers 460m and slower train covers 360m. The difference is 100m. This difference is between faster train's front edge and slower train's back edge.
Then it involves the distance of both the trains, hence we need to divide 100m by 2 (because in the question they've given as both the trains of equal length) to get the length of the train.
Then it involves the distance of both the trains, hence we need to divide 100m by 2 (because in the question they've given as both the trains of equal length) to get the length of the train.
Anoop said:
1 decade ago
I didn't understand that why we are considering speed of slower train even its mention that faster crosses the slower one.
Ashwini said:
1 decade ago
Why did you take 36 again two times please explain?
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