Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
493 comments Page 40 of 50.
Shobi said:
1 decade ago
Hi friends,
I ave confuesion in relative speed. Can I have some more explanation about relative speed?
I ave confuesion in relative speed. Can I have some more explanation about relative speed?
NIRMAL said:
1 decade ago
Vijay Kumar Kuppani you did solve problem very nicely again thanks.
AKHIL said:
1 decade ago
18/5 = 1 km/hr = 1000/3600 m/s
= 10/36 m/s
= 5/18 m/s.
= 10/36 m/s
= 5/18 m/s.
Vinod salunke said:
1 decade ago
Nice explanation by ramesh chandra.
Uma said:
1 decade ago
Manoj explanation s superb. Thank you.
Ahmed said:
1 decade ago
Explanation given by ramesh chandra is very good and short, Please follow his process without wasting your time.
We need such a good explanation like that.
We need such a good explanation like that.
Hari said:
1 decade ago
Excuse me? Why we divided 125 with 10?. Please explain me.
Preethi said:
1 decade ago
Thanks Abhishek now I clear about relative speed.
Preethi said:
1 decade ago
You are right kirubha. Nice explanation challu.
Challu said:
1 decade ago
Think you are in a train, another one moving side by you in parallel, what will you experience? the train is in less speed of actualone. To find original speed you have to add your train speed.
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