Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
493 comments Page 39 of 50.
Sada said:
1 decade ago
Any basic formula is there for this problem kindly explain.
PRADYUMNA KUMAR DAS said:
1 decade ago
If the man and train in opposite direction then it relative speed is x+5. And speed is x+5=45. =>x=40. Am I right?
Greeshma reddy said:
1 decade ago
How did this equation x-5=45 form?
Sanghaniakshay said:
1 decade ago
Thanks abhishek.
Ambikun said:
1 decade ago
There is no need of calculating relative speed. It can be solved easily by calculating the distance traveled by the man in 10 sec and the total distance covered by the train in the same time. This is very simple.
Parvez khan said:
1 decade ago
How was the relative speed calculated ?
Anish said:
1 decade ago
Hi Manishkumar,Vijaykumarkuppani,Umesh
U hav cleard the points exactly how itz done.
Thanks a lot...
U hav cleard the points exactly how itz done.
Thanks a lot...
Ranjit R Pawar said:
1 decade ago
Thanks rahul.
JRR said:
1 decade ago
Abhishek's answer explaines this clearly...Thanks Abhishek!!!
Shro said:
1 decade ago
Thanku Rahul. Your explanation was easy to understand and cleared my doubts too :).
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