Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
489 comments Page 49 of 49.
Rahul said:
2 decades ago
@gowtham
It would be only speed if the man(REFERENCE POINT) was stationary and only the train was moving. Here as both trian and REFERENCE POINT(man) are moving relative motion comes into picture.
It would be only speed if the man(REFERENCE POINT) was stationary and only the train was moving. Here as both trian and REFERENCE POINT(man) are moving relative motion comes into picture.
Vijayagopal said:
2 decades ago
Why 125/10 the 10 is divided 125 please explain it.
(2)
Gowtham said:
2 decades ago
Hey why we findind relative speed??? They asking only speed na????
(1)
Ankita said:
2 decades ago
Why its substracted?
(1)
Saji said:
2 decades ago
18/5 is to convert m/s to km/hr
(1)
Shwetha A V said:
2 decades ago
60*60/1000=18/5
(1)
M.saravanan said:
2 decades ago
Please explain 18/5.
(1)
Jothi said:
2 decades ago
Please explain to sutract -5 but ans is 50.
(4)
Swati said:
2 decades ago
Why is it divided by 18/5?
(2)
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