Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
475 comments Page 37 of 48.
Pankaj said:
7 years ago
Please explain 5/18 and 18/5.
Why using this?
Why using this?
Ruchitha said:
5 years ago
Why did we take x-5 for the speed? Explain it.
Karthik said:
9 months ago
125/10 = 12.5,
12.5 * 3.6 = 45,
45 + 5 = 50.
12.5 * 3.6 = 45,
45 + 5 = 50.
(22)
Preethi said:
1 decade ago
Abisheks answer is realy nice. Thank you abi.
PREM KUMAR said:
9 years ago
What are the formulas used to find the time?
Laxman said:
9 years ago
Nice & excellent explanations, Thank you all.
Sathish Chandran said:
8 years ago
May I know why we multiply the speed by 18/5?
Neha Kumari said:
11 months ago
How answer is 50 km/hr? Please explain to me.
(4)
REKHA said:
1 decade ago
Ramesh chandran.
CLEAR explanaTION. THANKS.
CLEAR explanaTION. THANKS.
Andrews Anbarasu said:
7 years ago
Your explanation is good @Ravi.
Thanks all.
Thanks all.
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