Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
493 comments Page 36 of 50.
Ajay said:
9 years ago
As per my calculation, 50 km/hr is the right answer.
Suraj Kumar Swami said:
8 years ago
x-5 = 45 the result should be 40, then why it is 50?
Kiran said:
6 months ago
@Naveen reddy.
Why adding +5? please explain to me.
Why adding +5? please explain to me.
(7)
Vijayagopal said:
2 decades ago
Why 125/10 the 10 is divided 125 please explain it.
(2)
Abhiroop said:
1 month ago
@Aswitha.
That is converting the m/sec into km/hr.
That is converting the m/sec into km/hr.
(1)
Muhammed areeb said:
1 decade ago
Why use 60*60/1000(18/5) I do not understand that?
Bharat Gupta said:
8 years ago
Please explain the relative speed = (x - 5) km/hr.
Sanika prakash said:
11 months ago
Good answer. Thanks all for explaining the answer.
(14)
Preethi said:
1 decade ago
Thanks Abhishek now I clear about relative speed.
Sai krishna. B said:
6 years ago
Why 60*60/1000 came here? Can you please explain?
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