Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
487 comments Page 38 of 49.
PREM KUMAR said:
10 years ago
What are the formulas used to find the time?
Laxman said:
9 years ago
Nice & excellent explanations, Thank you all.
Sathish Chandran said:
9 years ago
May I know why we multiply the speed by 18/5?
Neha Kumari said:
2 years ago
How answer is 50 km/hr? Please explain to me.
(4)
REKHA said:
2 decades ago
Ramesh chandran.
CLEAR explanaTION. THANKS.
CLEAR explanaTION. THANKS.
Andrews Anbarasu said:
8 years ago
Your explanation is good @Ravi.
Thanks all.
Thanks all.
Naveen reddy said:
10 months ago
125/10 = 12.5,
12.5 * 3.6 = 45,
45 + 5 = 50.
12.5 * 3.6 = 45,
45 + 5 = 50.
(35)
Jothi said:
2 decades ago
Please explain to sutract -5 but ans is 50.
(4)
Navaneedhar said:
1 decade ago
Please explain the subtract value of (x-5)?
Abdus salam said:
8 years ago
Thanks a lot for all the given explanation.
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