Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
493 comments Page 33 of 50.

Sushanth ratan said:   9 years ago
@Jothi.

-5 if it goes on the other side it becomes plus (+).

Naveen said:   5 years ago
I can't understand this sum please anyone explain me briefly.

Sahil said:   1 decade ago
Nice answer with explanation. It is very easy to understand.

Sada said:   1 decade ago
Any basic formula is there for this problem kindly explain.

Bala said:   9 years ago
Why are you divided 125/10 at the 1st step? Please explain.

Vipin said:   8 years ago
Hi, I am not getting this. Please anyone help me to get it.

Hari said:   1 decade ago
Excuse me? Why we divided 125 with 10?. Please explain me.

Krishna said:   1 decade ago
Is there any shortcut method to learn the relative motion?

Lakshmi said:   6 years ago
Relative speed subtracted by actual speed so we get X - 5.

Webisa Ibrahim said:   2 years ago
I am not getting this. Anyone, help me to understand this.
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