Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
493 comments Page 34 of 50.
Iyyanar said:
1 decade ago
Please give a clear cut definition for relative velocity.
Satish said:
1 decade ago
What is the need of taking 15/10 and explain how it came?
Gilbert said:
9 years ago
I think, 18/5 is seconds per meter not metres per second.
Dk singh said:
8 years ago
I think, 18/5 is seconds per meter not metres per second.
Hemant said:
2 months ago
Really Good Question. Very useful. Thanks for solving it.
(3)
Dattatray said:
2 decades ago
18/5 = 1 km/hr = 1000/3600 m/s
= 10/36 m/s
= 5/18 m/s.
= 10/36 m/s
= 5/18 m/s.
(1)
Jelli said:
2 decades ago
Thanks to all.
I got many idea's to solve this problem.
I got many idea's to solve this problem.
AKHIL said:
1 decade ago
18/5 = 1 km/hr = 1000/3600 m/s
= 10/36 m/s
= 5/18 m/s.
= 10/36 m/s
= 5/18 m/s.
Manjunath said:
9 years ago
Hi, anyone please explain to me why we should take 5/18?
Satya said:
8 years ago
Why is it divided by 18/5 and how it is? Please explain.
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