Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
475 comments Page 34 of 48.
Jelli said:
1 decade ago
Thanks to all.
I got many idea's to solve this problem.
I got many idea's to solve this problem.
AKHIL said:
1 decade ago
18/5 = 1 km/hr = 1000/3600 m/s
= 10/36 m/s
= 5/18 m/s.
= 10/36 m/s
= 5/18 m/s.
Manjunath said:
8 years ago
Hi, anyone please explain to me why we should take 5/18?
Satya said:
7 years ago
Why is it divided by 18/5 and how it is? Please explain.
Swati warang said:
7 years ago
What is relative speed, can you explain in simple terms?
Suman said:
1 decade ago
Here given that (x-5) km/hr. What is 5? Please explain.
Mayurkapse said:
10 years ago
18/5 divided because the conversion of m/sec to km/hr.
Ladura said:
7 years ago
What is the distance covered by the man in 10 seconds?
Abinaya said:
4 years ago
Why we should reciprocal 5/18 to 18/5? Please explain.
Gayu said:
1 decade ago
Why its divided by 15/8? need some brief explanation.
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