Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
475 comments Page 32 of 48.
Bunny said:
4 years ago
Why the speed of the train is calculated by 125 meters by 10sec?
(6)
Tahira said:
1 decade ago
Hai fnds.
Howz the 12.5 is converted into 25.
Please explain.
Howz the 12.5 is converted into 25.
Please explain.
Monisha said:
1 decade ago
Great job guys!!! I understood well than my faculty teaches...
JRR said:
1 decade ago
Abhishek's answer explaines this clearly...Thanks Abhishek!!!
Bibin said:
1 decade ago
Why you made it 18/5, earlier it was 5/18, please explain me.
Sushanth ratan said:
8 years ago
@Jothi.
-5 if it goes on the other side it becomes plus (+).
-5 if it goes on the other side it becomes plus (+).
Naveen said:
4 years ago
I can't understand this sum please anyone explain me briefly.
Sahil said:
9 years ago
Nice answer with explanation. It is very easy to understand.
Sada said:
1 decade ago
Any basic formula is there for this problem kindly explain.
Bala said:
8 years ago
Why are you divided 125/10 at the 1st step? Please explain.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers