Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
493 comments Page 29 of 50.
Siva laxman said:
9 years ago
The relatie speed of the train = if opp direction = s1+s2.
Same direction s1~s2.
Same direction s1~s2.
Supriyo Das said:
5 months ago
@Kiran.
There is x - 5 = 45 which means x = 45 + 5.
So, the result will be 50.
There is x - 5 = 45 which means x = 45 + 5.
So, the result will be 50.
(3)
Preetha said:
1 decade ago
Hi friends, I can't understand this please anyone help me in some other method.
Pradeep said:
1 decade ago
Can you please explain me what is relative speed here and why it is used here ?
Ravindra said:
1 decade ago
X-5 = 45 is right because train and man same side. In same side it is correct.
Sheital saira said:
3 years ago
@Hemanth sairam.
Why 60 mins and 60 seconds taken there?
Please explain me.
Why 60 mins and 60 seconds taken there?
Please explain me.
(19)
San said:
2 decades ago
I cant understand relative speed formula ie) x-5 is this standard formula ?
Onam said:
2 decades ago
5/18 is conversion of km/hr to m/s and 18/5 is conversion digit m/s to km/s
Mani said:
2 decades ago
Hi Tahira,
You just cancel 125/10 using multiples of 5.
125/10=25/2=12.5.
You just cancel 125/10 using multiples of 5.
125/10=25/2=12.5.
Rony shaha said:
9 years ago
Speed*time=distance or pole's length,
How I can calculate length of train?
How I can calculate length of train?
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