Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
475 comments Page 29 of 48.
Sheital saira said:
2 years ago
@Hemanth sairam.
Why 60 mins and 60 seconds taken there?
Please explain me.
Why 60 mins and 60 seconds taken there?
Please explain me.
(19)
San said:
1 decade ago
I cant understand relative speed formula ie) x-5 is this standard formula ?
Onam said:
1 decade ago
5/18 is conversion of km/hr to m/s and 18/5 is conversion digit m/s to km/s
Mani said:
1 decade ago
Hi Tahira,
You just cancel 125/10 using multiples of 5.
125/10=25/2=12.5.
You just cancel 125/10 using multiples of 5.
125/10=25/2=12.5.
Rony shaha said:
8 years ago
Speed*time=distance or pole's length,
How I can calculate length of train?
How I can calculate length of train?
Jansi said:
1 decade ago
Could you explain how to calculate downstream in still water with example?
Shikhar Singh said:
10 years ago
Thanks for all related answer its easier for me too solve query like this.
Nagamani said:
10 years ago
In the given question 5 km\hr. So why you are calculated only km per hour?
Bouvthika R.M said:
7 years ago
Here please explain for what reason it becomes (X-5).
I can't understand.
I can't understand.
MammuChowdary said:
1 decade ago
Moving in same direction : SUBTRACT.
Moving in opposite direction : ADD.
Moving in opposite direction : ADD.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers