Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 28 of 48.

Shro said:   1 decade ago
Thanku Rahul. Your explanation was easy to understand and cleared my doubts too :).

Rishabh Suthar said:   9 years ago
Same direction then we do subtract and opposite direction then we do addition. Why?

Shabana said:   1 decade ago
Hi, Really the explanation given by Dattatray & Rahul was superb. Thanks guys.

Hemavathy said:   1 decade ago
How the will be 50?
Speed = 25/2(m/s).

Converting(m/s)to(km/hr).
25/2*18/5 = 45.

Sarah said:   1 decade ago
Hi I can't understand friends. What is this x-5 ?

Please anyone explain clearly.

Velu said:   1 decade ago
Here they are asking the train speed. But why we are finding the relative speed.

Siva laxman said:   8 years ago
The relatie speed of the train = if opp direction = s1+s2.
Same direction s1~s2.

Preetha said:   1 decade ago
Hi friends, I can't understand this please anyone help me in some other method.

Pradeep said:   1 decade ago
Can you please explain me what is relative speed here and why it is used here ?

Ravindra said:   1 decade ago
X-5 = 45 is right because train and man same side. In same side it is correct.


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